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777dan777 [17]
3 years ago
12

SOMEONE HELP ME PLSS​

Physics
2 answers:
lara31 [8.8K]3 years ago
7 0
1. 2500/60 joules/sec
2. 2,500Nm
dsp733 years ago
4 0

Answer:

Explanation:

1 minute =60 second

power=work done/time taken

=2500/60

=41.66 watt

work=force *displacement

=500 N * 100 m

=50000 joule

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Answer:

x_2=1.60m

Explanation:

From the Question We are told that

Initial Force F_1=5800N

Final Force F_2=6500N

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Since

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Therefore

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 x_1=3.20-x_2

Generally the equation for The center of mass is at x_2 is mathematically

given by

 x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}

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6 0
2 years ago
You are trying to overhear a juicy conversation, but from your distance of 20.0 m , it sounds like only an average whisper of 30
12345 [234]

Answer:

r₂ = 0.2 m

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given,

distance = 20 m

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now,

30 = 10 log(\dfrac{I_1}{10^{-12}})

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to hear the whisper sound = 80 dB

80 = 10 log(\dfrac{I_2}{10^{-12}})

\dfrac{I_2}{10^{-12}}= 10^8

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\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}

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6 0
3 years ago
Which occurrence would lead you to conclude that lights are connected in a
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Answer:B When one bulb burns out, all the others lights stay lit.

Explanation:

3 0
3 years ago
Starting from zero, the electric current takes 2 seconds to reach half its maximum possible value in an RL circuit with a resist
Leno4ka [110]

Answer:

time=4s

Explanation:

we know that in a RL circuit with a resistance R, an inductance L and a battery of emf E, the current (i) will vary in following fashion

i(t)=\frac{E}{R}(1-e^\frac{-t}{\frac{L}{R}}), where imax=\frac{E}{R}

Given that, at i(2)=\frac{imax}{2} =\frac{E}{2R}

⇒\frac{E}{2R}=\frac{E}{R}(1-e^\frac{-2}{\frac{L}{R}})

⇒\frac{1}{2}=1-e^\frac{-2}{\frac{L}{R}}

⇒\frac{1}{2}=e^\frac{-2}{\frac{L}{R}}

Applying logarithm on both sides,

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Now substitute i(t)=\frac{3}{4}imax=\frac{3E}{4R}

⇒\frac{3E}{4R}=\frac{E}{R}(1-e^\frac{-t}{\frac{L}{R}})

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⇒\frac{1}{4}=e^\frac{-t}{\frac{L}{R}}

Applying logarithm on both sides,

⇒log(\frac{1}{4})=\frac{-t}{\frac{L}{R}}

⇒log(4)=\frac{t}{\frac{L}{R}}

⇒t=log4\frac{L}{R}

now subs. \frac{L}{R}=\frac{2}{log2}

⇒t=log4\frac{2}{log2}

also log4=log2^{2}=2log2

⇒t=2log2\frac{2}{log2}

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5 0
3 years ago
A car started from a rest and accelerated at 9.54 m/s2 for 6.5 seconds. How much distance was covered by the car?
ElenaW [278]

Explanation:

S =ut + 1/2at^2

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3 years ago
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