1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
777dan777 [17]
3 years ago
12

SOMEONE HELP ME PLSS​

Physics
2 answers:
lara31 [8.8K]3 years ago
7 0
1. 2500/60 joules/sec
2. 2,500Nm
dsp733 years ago
4 0

Answer:

Explanation:

1 minute =60 second

power=work done/time taken

=2500/60

=41.66 watt

work=force *displacement

=500 N * 100 m

=50000 joule

You might be interested in
How much positive electric charge is in 10 moles of carbon? NA=6.022×1023mol−1, e=1.60×10−19C.
levacccp [35]

Answer:

4.75 x 10^-25 kg

Explanation:

5 0
3 years ago
A man weighing 680N and a woman weighing 500N have the same momentum. What is the ratio of the man's kinetic energy Km to that o
svet-max [94.6K]

Answer:

\dfrac{K_m}{K_w}=0.734

Explanation:

given,

weight of the man = 680 N

weight of the woman = 500 N

mass of man = \dfrac{680}{9.8}

  M_m = 69.4 Kg

mass of woman

= \dfrac{500}{9.8}

M_w = 51 Kg

ratio of man's kinetic energy Km to that of the woman Kw

\dfrac{K_m}{K_w}=\dfrac{\dfrac{P_m^2}{2M_m}}{\dfrac{P_w^2}{2M_w}}

momentum is same

\dfrac{K_m}{K_w}=\dfrac{2M_w}{2M_m}

\dfrac{K_m}{K_w}=\dfrac{M_w}{M_m}

\dfrac{K_m}{K_w}=\dfrac{51}{69.4}

\dfrac{K_m}{K_w}=0.734

3 0
4 years ago
A typical atom has a diameter of about 1.32 x 10-10 m. (a) what is this in inches (b) approximately how many atoms arethere alon
JulijaS [17]

Answer:

A ) 5.197 \times 10 ^{-9} inches

b) There are approximately 100,000,000 atoms on the 1.32 cm lines

Explanation:

To ensure the accuracy of our answer, we will have to make sure we work in the appropriate units.

A

To convert    1.32 \times 10^{-10}   m to inches, we can use this factor.

1 m = 39.3701 inches

Therefore 1.32 \times 10^{-10}   m =  

B

To find the number of atoms on a 1.32 cm line, we will first of all need to convert 1.32 cm to meters.

1.32 cm = 0.0132 metres (divided 1.32 by 100 to convert to metres)

Assuming all the atoms are arranged side by side, with their edges touching on the 0.0132m line, the number of atoms present will be

0.0132/1.32\times 10^{-10} = 100,000,000 atoms

5 0
3 years ago
A crane used 250,000 Joules of work to move a beam to the top of a building in 20 seconds. How much power did the crane use?
maria [59]

Answer:

12500W

Explanation:

Given parameters:

Work done  = 250000J

Time taken  = 20s

Unknown:

Power of the crane = ?

Solution:

Power is the defined as the rate at which work is being done;

  Mathematically;

        Power = \frac{work done}{time }

 insert the parameters and solve;

      Power  = \frac{250000}{20}   = 12500W

7 0
3 years ago
Which statement describes a question that can be answered by a scientific
goblinko [34]
It’s d! hope I can help
4 0
4 years ago
Read 2 more answers
Other questions:
  • State the universal law of gravitation
    7·1 answer
  • At what temperature will water begin to boil and turn to steam?
    10·2 answers
  • What is the velocity of all electromagnetic waves in a vacuum?
    14·1 answer
  • A charge Q creates an electric field. A test charge q is usedto measure the strength of the electric field at a distance d from
    9·1 answer
  • The amount of carbon dioxide released into the atmosphere is balanced by the release of:
    7·2 answers
  • I need help for A-B-C-D-E please:)
    5·1 answer
  • One of the ways that scientists determine the distance between Earth and other objects in space is to send light waves toward an
    11·1 answer
  • What physical property does gases and plasmas have in common
    5·2 answers
  • Why is a white car an example of a poor blackbody radiator?
    14·1 answer
  • A 60 year old person has a threshold of hearing of 79.0 dB for a sound with frequency f=10,000 Hz. By what factor must the inten
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!