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ipn [44]
3 years ago
9

I need help with these questions :(see image )

Physics
1 answer:
maw [93]3 years ago
7 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>

\huge\boxed{Theta=25.67}

<h2>_____________________________________</h2><h3>DATA:</h3>

Range = R = 78m

Initial Velocity = V_i = 30m/s

Angle(theta) = ?

<h2>_____________________________________</h2><h3>SOLUTION:</h3>

The Range is given by,

                                    R =\frac{V_0^2}{g}Sin2(theta)\\\\78 = \frac{30^2}{10}Sin2(theta)\\\\Sin2(theta) = \frac{780}{900}\\\\Sin2(theta) = \frac{13}{15}\\\\Sin(theta) = \frac{13}{30}\\\\theta = Sin^{-1}\frac{13}{30}\\\\theta = 25.67^0

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
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3 years ago
a passing warm front changes air pressure. does a passing warm front increase or decrease air pressure
meriva
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How much smaller is an atom than a speck of dust
IceJOKER [234]

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an atom is about a trillion times smaller then a speck of dust.

Explanation:

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4 years ago
Which component of an atom contains the MAJORITY<br> of its mass?
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3 years ago
The magnetic field at the center of a 1.40-cm-diameter loop is 2.50 mT . PART A) What is the current in the loop?
NISA [10]

Explanation:

It is given that,

Diameter of loop, d = 1.4 cm

Radius of loop, r = 0.7 cm = 0.007 m

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(A) Magnetic field of a current loop is given by :

B=\dfrac{\mu_oI}{2r}

I is the current in the loop

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 2.5\times 10^{-3}\times 0.007}{4\pi \times 10^{-7}}

I = 27.85 A

(B) Magnetic field at a distance r from a wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

r=\dfrac{\mu_o I}{2\pi B}

r=\dfrac{4\pi \times 10^{-7}\times 27.85}{2\pi \times 2.5\times 10^{-3}}

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3 years ago
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