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Misha Larkins [42]
3 years ago
14

Is this correct please help!

Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

Almost...

The correct answer would be

To find the area of the base, multiply 15 times 16 then divide by 2

Then multiply by 19 to find the volume of the shape

Step-by-step explanation:

The base is a triangle

The area of a triangle = base length times height divided by 2

The triangle has a base length of 16 and a height of 15

So to find the area of the base we multiply 15 times 16 and divide that by 2

The volume of a prism is equal to the area of the base times the length of the prism

The length of the prism is 19 so we would then multiply by 19

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3 years ago
If f(3)=191.5 when r =0.03 for the function F(t)=pe^rt, then what is the approximate value of P?
ElenaW [278]

Answer:

A. 175

Step-by-step explanation:


5 0
3 years ago
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SNOG PLEASE HELP! (x-1)(y+8)
Leya [2.2K]

Answer:

Using FOIL we get:

xy + 8x - y - 8

4 0
3 years ago
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Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
ElenaW [278]

Answer:

x =  -2 ±sqrt(7)

Step-by-step explanation:

3x^2 +12 x = 9

Divide each side by 3

3x^2 /3 +12x/3 = 9/3

x^2 +4x = 3

Take the coefficient of x

4

Divide by 2

4/2 =2

Square it

2^2 =4

Add it to each side

x^2 +4x+4 = 3+4

x^2 +4x+4 = 7

(x+2)^2 = 7

Take the square root of each side

x+2 = ±sqrt(7)

Subtract 2 from each side

x+2-2 = -2 ±sqrt(7)

x =  -2 ±sqrt(7)

3 0
3 years ago
If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.
Zina [86]

Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s

(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = \frac{y(b)-y(a)}{b-a}

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t^2.

(a)

(i) average speed = \frac{y(2)-y(1)}{2-1}

=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}

=50.42 m/s

(ii) average speed = \frac{y(1.5)-y(1)}{1.5-1}

=\frac{56(1.5)-1.86(1.5)^2-(56(1)-1.86(1)^2)}{0.5}

=51.35m/s

(iii) average speed = \frac{y(1.1)-y(1)}{1.1-1}

=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}

=52.094m/s

(iv) average speed = \frac{y(1.01)-y(1)}{1.01-01}

=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}

=52.2614
m/s

(v) average speed = \frac{y(1.001)-y(1)}{1.001-01}

=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}

=52.27814
m/s

(b) y(1)=56(1)-1.86(1)^2

=56-1.86

= 54.14 m/s

3 0
3 years ago
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