The width of a rectanle is 8n - 8.5 feet and the lenght is 8.5n + 10 feet. Find the perimeter of the rectangle
1 answer:
Answer:
The perimeter of a rectangle is:
- P = 33n+3
Step-by-step explanation:
Given
The width of a rectangle w = 8n - 8.5 feet
The length of a rectangle l = 8.5n + 10 feet
To determine
The perimeter of a rectangle = P = ?
The perimeter of a rectangle can be determined using the formula
substitute l = 8.5n + 10 and w = 8n - 8.5
Therefore, the perimeter of a rectangle is:
- P = 33n+3
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Answer:
- maximum: (x, y) = (12.4n+3.2, 186.322)
- minimum: (x, y) = (12.4n+9.4, 163.498)
Step-by-step explanation:
You know that cos(α) is a maximum at α=0, 2π, 4π, and all even multiples of π. You know cos(α) is a minimum for α=π, 3π, 5π, and all odd multiples of π.
You can find your value of x at which y will be a maximum by setting the argument of the cosine function equal to zero (and/or 2nπ). If we use α=2nπ, then we have ...
α = (5π/31)(x -3.2) = 2nπ
(x -3.2) = (31/5)(2n) = 12.4n
Tidal maxima will occur at ...
x = 12.4n +3.2 . . . . . for integer values of n
Without bothering to go through the solution for α being odd multiples of π, we can see from this that the period is 12.4 hours. We know the tidal minimum will be half a period later, or 6.2 hours later than this.
Tidal minima will occur at ...
x = 12.4n +9.4 . . . . for integers n
__
Of course, cos(α) has extremes of ±1, so your tidal maximum will be ...
y = 11.412 +174.91 = 186.322
and your tidal minimum will be ...
y = -11.412 +174.91 = 163.498
