K: 157.8g CaCl2
U: ? mol CaCl2
1Ca = 1(40.08) = 40.08
2 Cl = 2(35.45) =+ 70.90
110.98
157.8g CaCl2 1 mol CaCl2
1 mol CaCl2 110.98g CaCl2
<span>The water will diffuse through the membrane until there is an equal concentration of solute and water on both sides.</span>
14.5 M
Molarity=grams/liters
M=58/4.0
Answer:
Matthias Schleiden, Theodor Schwann, and Rudolf Virchow
Explanation:
