Question

Empirical formula C2H2O Experimental molar mass 216 g/mol

Answer 1

Answer:

Molecular formula of the compound is $C_{2}H_{2}O=C_{10}H_{10}O_{5}$

Explanation:

Empirical formula of the given compound - $C_{2}H_{2}O$

Empirical formula mass = $(2\times 12g/mol)+(2\times 1g/mol)+(16 g/mol)=42g/mol$

$\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}$

$\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}= 5.15=5$

${Molecular\,formula}= 5\times {Empirical\,formula}$

$= 5\times C_{2}H_{2}O=C_{10}H_{10}O_{5}$

Therefore, molecular formula of the compound is $C_{2}H_{2}O=C_{10}H_{10}O_{5}$