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Kryger [21]
4 years ago
12

Empirical formula C2H2O Experimental molar mass 216 g/mol

Chemistry
1 answer:
IgorLugansk [536]4 years ago
3 0

Answer:

Molecular formula of the compound is C_{2}H_{2}O=C_{10}H_{10}O_{5}

Explanation:

Empirical formula of the given compound - C_{2}H_{2}O

Empirical formula mass = (2\times 12g/mol)+(2\times 1g/mol)+(16 g/mol)=42g/mol

\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}

\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}= 5.15=5

{Molecular\,formula}= 5\times {Empirical\,formula}

= 5\times C_{2}H_{2}O=C_{10}H_{10}O_{5}

Therefore, molecular formula of the compound is C_{2}H_{2}O=C_{10}H_{10}O_{5}

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Free_Kalibri [48]

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Explanation:

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7 0
3 years ago
what is the trend for the size as you go from Be to Mg to Ca? does the atomic size increase, decrease, or remain the same? how w
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Answer:

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Explanation:

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Ca 20 1s2 /2s2 2p6/3s2 3p6 3d/4s2

see that all the elements are in the same group but are in different period

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4 0
4 years ago
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LenKa [72]

Answer:

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Explanation:

4 0
3 years ago
Read 2 more answers
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