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Kryger [21]
4 years ago
12

Empirical formula C2H2O Experimental molar mass 216 g/mol

Chemistry
1 answer:
IgorLugansk [536]4 years ago
3 0

Answer:

Molecular formula of the compound is C_{2}H_{2}O=C_{10}H_{10}O_{5}

Explanation:

Empirical formula of the given compound - C_{2}H_{2}O

Empirical formula mass = (2\times 12g/mol)+(2\times 1g/mol)+(16 g/mol)=42g/mol

\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}

\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}= 5.15=5

{Molecular\,formula}= 5\times {Empirical\,formula}

= 5\times C_{2}H_{2}O=C_{10}H_{10}O_{5}

Therefore, molecular formula of the compound is C_{2}H_{2}O=C_{10}H_{10}O_{5}

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