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Vilka [71]
3 years ago
13

A 12.8 g piece of aluminum (which has a molar heat capacity of 24.03 j/°c·mol) is heated to 82.4°c and dropped into a calorimete

r containing water (specific heat capacity of water is 4.18 j/g°c) initially at 22.3°c. the final temperature of the water is 25.7°c. ignoring significant figures, calculate the mass of water in the calorimeter.

Chemistry
1 answer:
BARSIC [14]3 years ago
5 0
The mass of Water in Calorimeter is approximately 118 grams, here is the solution:

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The melting point of H₂O(s) is 0 °C. Would you expect the melting point of H₂S(s) to be 85 °C, 0 °C or -85 °C.? Justify your cho
dimulka [17.4K]

Answer:

-85 °C

Explanation:

O and S are in the same group( Group 16). Since S is below O it's atomic mass is higher than O. So molar mass of H2S is higher than H2O. The strength of Vanderwaal Interactions ( London dispersion forces) increases when the molar mass increases. However, only H2O can form H bonds with each other. This is because electronegativity of O is higher than S and therefore H in H2O has a higher partial positive charge than H of H2S.

H bond dominate among these 2 types of forces so the strength of attractions between molecules is higher in H2O than H2S. Therefore more energy should be supplied for H2O to break inter

molecular forces and convert from solid to liquid state than H2S. So mpt of H2O must be higher than that of H2S.

5 0
3 years ago
4.50 g of NaCl reacts with 10.00 g of AgNO3 to produce 7.93 g of AgCl. If the theoretical amount of AgCl that can be formed is 8
olga nikolaevna [1]

Answer: 94.07%

Explanation:

Percentage yield can be calculated by the formula

%yield = Experimental yield/Theoretical yield x100

Experimental yield = 7.93g

Theoretical yield = 8.43

%yield = Experimental yield/Theoretical yield x100

%yield = 7.93/8.43 x 100 = 94.07%

4 0
3 years ago
1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
USPshnik [31]

Answer:

\%\ Error = 21.5\%

Explanation:

Given

Measured = 24.5

Actual = 31.2

Required

Determine the percentage error

First, we need to determine the difference in the measurement

Difference = |Actual - Measured|

Difference = |31.2 - 24.5|

Difference = |6.7|

Difference = 6.7

The percentage error is calculated as thus:

\%\ Error = \frac{Difference * 100\%}{Actual}

\%\ Error = \frac{6.7 * 100\%}{31.2}

\%\ Error = \frac{670\%}{31.2}

\%\ Error = 21.4743589744\%

\%\ Error = 21.5\% <em>approximated</em>

6 0
3 years ago
What piece of equipment is used to measure: length
avanturin [10]

Answer:

Ruler

Explanation:

Ruler and eraser kakgjwjeigidiifigig

8 0
3 years ago
Read 2 more answers
A 4kg bowling ball is held 2.5 meters above your head. A 0.5 kg tennis ball is held at 12 meters above your head. Which one has
Anettt [7]

Answer:

P.E for the 4kg bowling ball held 2.5 meters above head is 100j, while the other is 60j so the 4kg ball has more potential energy

7 0
3 years ago
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