Answer:
Heat of vaporization.
Explanation:
the amount of energy needed to change the specific amount or gram of liquid in to gas phase is called heat of vaporization.
In this liquid is converted into gas phase as because after the boiling point addition of more energy will cause breakage of bonds present in between the liquid molecules which results in the vaporization of liquid.
Density measures how tightly packed particles are.
If particles are tightly packed together, they will be more dense.
If they are loosely together, they will be less dense.
However, a common mistake is thinking that if something
is more dense it means that it's heavier.
However, that's not the case.
It has to do with how particles are packed in an object.
Answer:
A fund manager has portfolio worth $50 million with a beta of 0.87. The manager is concerned about the performance of the market over the next two months and plans to
use 3-month future contracts on the S&P 500 to hedge the risk.
In order to answer this, we mus know the data for the heat of combustion of propane. This is an empirical data that you can search online. The heat of combustion is -2220 kJ/mol. The molar mass of propane of 44.1 g/mol. The solution is as follows:
ΔH = -2220 kJ/mol (1 mol/44.1 g)(1000g/1kg)(20 kg)
<em>ΔH = -1006802.721 kJ or -1 GJ</em>
6 electrons if only 3 of the orbitals of D are being used. The D section can have a max of 10 electrons, hope this helped.
