This is an incomplete question, here is a complete question.
Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.
Answer : The specific heat of a material is, 0.137 J/g.K
Explanation :
Formula used to calculate the specific heat of a material is:
where,
q = heat absorbed = 96 J
m = mass of sample = 35 g
c = specific heat capacity of material = ?
= initial temperature = 293 K
= final temperature = 313 K
Now put all the given values in the above formula, we get:
Therefore, the specific heat of a material is, 0.137 J/g.K
Answer:
The phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours
Explanation:
The crossing to determine the offsprings is shown in the image attached where we have two green (Yy) seeds and two yellow (yy) seeds as offsprings.
Thus, <u>the phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours</u>.
Note, the dominant allele is "Y" while the recessive allele is "y". Thus, Yy would produce a yellow colour while yy would produce a green colour (as both mentioned in the question).
Also note that phenotype describes the outward properties/characteristics of an individual.
Answer:
Periodic table of elements
Explanation:
Rock a is a sedimentary and rock B is a sediment rock also known as sandstone
The distributive property would work best
