Answer:
10.23 grams of sucrose should be added.
Explanation:
1.15 m means molality (moles of solute in 1kg of solvent)
1.15 moles of sucrose are contained in 1 kg of solvent (1000 g)
Let's determine the moles in our mass of solvent.
Firstly we convert the g to kg → 26 g . 1kg/1000g = 0.026 kg
m . mass (kg) = 1.15 mol/kg . 0.026kg → 0.0299 moles.
Finally we convert the moles to mass (mol . molar mass)
0.0299 mol . 342.3 g/mol = 10.23 g
The answer is homogenous i think
They are three types of mixtures:
-solutions : they are homogeneous mixtures of 2 or more sub. in a single phase.
-suspensions: if the particles in a solvent are so large that they settle out unless constantly tired, the mixture is called a suspension.
-colloids: particles that are intermediate in size between those of solutions and suspensions form mixtures called colloids.
:)
Answer:
Explanation:
Hello there!
In this case, since the equation for the calculation of dilutions is:
Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:
Best regards!
