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ser-zykov [4K]
3 years ago
8

Find the equation of a line which has a slope of -9 and crosses the y axis at -7

Mathematics
1 answer:
Ymorist [56]3 years ago
6 0

Answer:

4

Step-by-step explanation:

slope,m=0 and y-intercept (0,4) means this is a horizontal line that crosses the y-axis at 4. so, y=mx+b becomes y=b or y=4 which is the equation of given line.

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11 months ago
The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

* if x>1, then x-1>0.

* Also since the parabola opens up, then y>5.

So let's solve y=(x-1)^2+5 for x.

Subtract 5 on both sides:

y-5=(x-1)^2

Take square root of both sides:

Plus/minus sqrt(y-5)=x-1

We want x-1>0:

Sqrt(y-5)=x-1

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Sqrt(y-5)+1=x

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Sqrt(x-5)+1=y

x>5

y>1

3 0
3 years ago
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