The specific heat of the substance is 0.548 J/g/c
<u><em>calculation</em></u>
Specific heat is calculated using Q=MCΔT formula, where;
Q(heat)= 2510.0 j
M (mass)= 0.158 kg convert into g
= 1 Kg = 1000 g
0.158 kg= ? g
= (0.158 kg x 1000g) / 1 kg = 158 g
C( specific heat capacity) = ?
ΔT(change in temperature) = 61.0 -32c = 29 c
make C the subject of the formula by dividing both side by m andΔT
c= Q /mΔT
C= [2510.0 j / 158 g x 29] = 0.548 j/g/c