According to the second law, heat which is also referred to as thermal energy can be completely converted into work.
The second statement is much related directly to the second law.
We can say that some energy is lost while other is used to do work.
Answer:
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Answer:
85 K
Explanation:
T₀ = initial temperature of the gas = 77 K
T = final temperature of the gas = ?
n = number of moles of monoatomic gas = 1.00 mol
R = universal gas constant = 8.314
c = heat capacity at constant volume = (1.5) R = (1.5) (8.314) = 12.5
Q = Amount of heat absorbed = 100 J
Amount of heat absorbed is given as
Q = n c (T - T₀)
100 = (1) (12.5) (T - 77)
T = 85 K
a) create an expression
for the ball's initial horizontal velocity, V0x, in terms of the variables
given in the problem statement.
v0x = vf * cos(Θf)
<span>
b) calculate the ball's initial vertical velocity, V0y, in
m/s</span>
v0x = 32.4m/s * cos(-25.5º)
= 29.2 m/s <span>
tanΘ = v1y / v0x → tan(-25.5) = v1y / 29.2m/s → v1y = -13.93
m/s
the vertical velocity when the ball was caught.
(v0y)² = (v1y)² + 2as = (-13.93m/s)² + 2 * 9.8m/s² * 5.5m = 301.78
m²/s²
v0y = 17.37 m/s
c) calculate the magnitude of the ball's initial velocity,
v0, in m/s</span>
v0 = sqrt (v0y^2 +
v0x^2)
v0 = sqrt (17.37^2 + 29.2^2)
m/s
v0 = 33.98 m/s
<span>
d) find the angle, theta0, in degrees above the horizontal at
which which the ball left the bat.</span>
tan Θ = v0y/v0x
<span>Θ = arctan(17.37/29.2) =
30.75º above horizontal</span>