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3 years ago

Does ammonification increase or decrease biomass? How?

1 answer:

5 0

Hello! I'm not too knowledgeable on this topic, but I do know that ammonification is caused through different inorganic reactions. Or to metabolism systems of organisms. I also found it is a process in which nitrate reduction to nitrite is followed by the six-electron reduction of nitrite to ammonium.

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What is the kinetic energy of a 2995 kg truck when it moving 47 ms

Dafna11 [192]

To find the kinetic energy . You have to use this equation : 1/2m(v^2) .

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3 years ago

A parsec is a measurement of: magnitude distance position speed

guajiro [1.7K]

A parsec is a measurement of distance.

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3 years ago

Read 2 more answers

A person throws a ball straight up into the air with a speed of 7.3m/s. How high does the ball go?

Colt1911 [192]

Answer:

2.6645m

Explanation:

applying motion equations we can find the answer,

$v^{2}=u^{2} +2as$

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s = distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

$v^{2}=u^{2} +2as\\0=7.3^{2} -2*10*s\\s=2.6645m$

4 0

4 years ago

Which is a characteristic of the part of the atom marked "A"?Which is a characteristic of the part of the atom marked "A"?Which

WITCHER [35]

Here's link to the answer:

tinyurl.com/wpazsebu

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3 years ago

Read 2 more answers

a baby carriage is sitting at the top of a hill that is 21m high. the carriage with the baby weighs 25kg. calculate the speed th

Ulleksa [173]

Answer:

Velocity = 20.3 [m/s]

Explanation:

This is a typical problem of energy conservation, where potential energy is converted to kinetic energy. We must first find the potential energy. In this way, we will choose as a reference point or point where the potential energy is zero when the carrriage rolls down 21 [m] from the top of the hill.

$E_{p} =m*g*h\\ where:\\m = mass = 25[kg]\\g = gravity = 9.81 [m/s^2]\\h = elevation = 21 [m]\\E_{p} =potential energy [J]\\E_{p} =25*9.81*21=5150[J]$

Now this will be the same energy transformed into kinetic energy, therefore:

$E_{p}=E_{k} = 5150[J]\\E_{k} =0.5*m*v^{2} \\where:\\v=velocity [m/s]\\v=\sqrt{\frac{E_{k}}{0.5*25} } \\v=20.3[m/s]$

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3 years ago