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Sav [38]
3 years ago
11

The friction force between a bag and the floor is 4 N. what is the net force acting on the bag? What is the acceleration of the

bag?
Physics
1 answer:
tester [92]3 years ago
6 0
Well, if the bag is moving across the floor at a constant velocity. Then I would assume that the Fnet force is equal to 0, and thus the value of acceleration would also be equal to 0.
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The time constant for RC circuit with the values of R1 and C1 is 5ms. What will be the time constant for a new RC circuit with t
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Answer:

d. 25 ms

Explanation:

  • In a RC circuit we call time constant to the product of the resistance times the capacitance, which represents the time when the charge reaches to the 63% of the final value, as follows:

       \tau_{1} = R_{1} *C_{1}  = 5 ms (1)

  • If we have a new circuit with new values for R and C, the time constant will be defined in the same way, as follows:

       \tau_{2} =10* R_{1} *0.5*C_{1}  = 5*(R_{1}* C_{1}) = 5* \tau_{1} = 5* 5 ms = 25 ms (2)

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Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart
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The force exerted on the cart 2 during the collision is 2 N.

The given parameters:

  • <em>Mass of cart 1 = m1 = 1 kg</em>
  • <em>Mass of cart 2 = m2 = 2kg</em>
  • <em>Force applied on cart 1 = 2 N</em>

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.

F_1 = -F_2

F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N

Thus, the force exerted on the cart 2 during the collision is 2 N.

Learn more about Newton's third law of motion here: brainly.com/question/13874955

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