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stellarik [79]
3 years ago
8

Determine the pressure point in a liquid container within a pool. The height of the liquid column is 9 m, The density of the liq

uid is 997 kg/m^3, and gravity is 9.8 m/s^2.
Physics
1 answer:
7nadin3 [17]3 years ago
6 0

Absolute pressure: 1.89\cdot 10^5 Pa

Explanation:

The total pressure at a certain depth of a liquid is given by

p=p_0 + \rho g h

where

p_0 = 1.01\cdot 10^5 Pa is the atmospheric pressure

\rho is the density of the liquid

g is the acceleration of gravity

h is the depth of the liquid

For the liquid in this problem, we have

\rho=997 kg/m^3 is the density

g=9.8 m/s^2

h = 9 m is the column of liquid

Substituting, we find

p=1.01\cdot 10^5 + (997)(9.8)(9)=1.89\cdot 10^5 Pa

Learn more about pressure in a fluid:

brainly.com/question/9805263

#LearnwithBrainly

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The most likely theory of the formation of Earth's Moon is that it The most likely theory of the formation of Earth's Moon is th
Ann [662]

Answer:

Option (3)

Explanation:

According to researches done by the astronomers, it has been found that the earth collided with a giant Mars-size early proto-planet, whose name was 'Theia' during the Hadean era, about.5 billion years back. This collision resulted in the detachment of a considerably huge amount of material away from the earth. The remnant debris particles accumulated and gave rise to the formation of moon. The earth during that time was comprised of molten lava only, and from this collision, the earth attained its tilt of approximately 23.5°.

Thus, the correct answer is option (3).

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4 years ago
As rotational speed increases, thrust____?
never [62]
Increases exponentially is your correct answer
6 0
3 years ago
Two identical billiard balls traveling at the same speed have a head-on collision and rebound. If the balls had twice the mass,
Vinvika [58]

Answer:

a) No difference

Explanation:

Since the billiard balls are identical , they have the same mass. Also they have the same speed

Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

where m= mass , vi= initial velocity , vf= final velocity

since m1=m2=m , vi1=vi2=vi

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

m * v i² = 1/2 m (v f1² +v f2² )

vi² = 1/2(v f1² +v f2² )

since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf

therefore

v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²

and thus

vi= vf

in conclusion, there is no difference in speed after the rebound

4 0
3 years ago
12. An astronaut whose mass is 70 kg on Earth's surface 12 poi
Vadim26 [7]

Her mass is still 70 kg

Explanation:

The mass of an object is an intrinsec property of the object that gives a measure of the "amount of matter" inside the object.

Being an intrinsec property, it depends only on the object itself, not on its location: therefore, the mass of an object is always the same in different locations. Therefore, the mass of the astronaut in the spacecraft is still the same as if she was on the earth, 70 kg.

On the contrary, the weight of an object is the force of gravity acting on the object, and it is given by

F=mg

where

m is the mass

g is the acceleration of gravity

While m is always the same, the value of g changes based on the location: therefore, the weight of an object changes  depending on the location.

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3 0
3 years ago
Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field acting perpendicul
ANEK [815]

Answer:

4.14 cm.

Explanation:

Given,

For Coil 1

radius of coil, r₁ = 5.6 cm

Magnetic field, B₁ = 0.24 T

For Coil 2

radius of coil, r₂ = ?

Magnetic field, B₂ = 0.44 T

Using formula of maximum torque

\tau_{max}= NIAB

Since both the coil experience same maximum torques

now,

NIA_1B_1 = NIA_2B_2

A_1B_1 = A_2B_2

r_1^2 B_1 = r_2^2 B_2

5.6^2\times 0.24= r_2^2\times 0.44

r_2 = 4.14\ cm

Radius of the coil 2 is equal to 4.14 cm.

4 0
4 years ago
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