1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stellarik [79]
3 years ago
8

Determine the pressure point in a liquid container within a pool. The height of the liquid column is 9 m, The density of the liq

uid is 997 kg/m^3, and gravity is 9.8 m/s^2.
Physics
1 answer:
7nadin3 [17]3 years ago
6 0

Absolute pressure: 1.89\cdot 10^5 Pa

Explanation:

The total pressure at a certain depth of a liquid is given by

p=p_0 + \rho g h

where

p_0 = 1.01\cdot 10^5 Pa is the atmospheric pressure

\rho is the density of the liquid

g is the acceleration of gravity

h is the depth of the liquid

For the liquid in this problem, we have

\rho=997 kg/m^3 is the density

g=9.8 m/s^2

h = 9 m is the column of liquid

Substituting, we find

p=1.01\cdot 10^5 + (997)(9.8)(9)=1.89\cdot 10^5 Pa

Learn more about pressure in a fluid:

brainly.com/question/9805263

#LearnwithBrainly

You might be interested in
How many joules is 3 lightning bolts?
pogonyaev

Answer:

one billion to ten billion joules.

Explanation:

To keep a 100-watt light bulb going for one second, one hundred joules of energy will be used.

6 0
2 years ago
Read 2 more answers
g A ball thrown straight up into the air is found to be moving at 7.94 m/s after falling 2.72 m below its release point. Find th
kati45 [8]

The ball has height <em>y</em> and velocity <em>v</em> at time <em>t</em> according to

<em>y</em> = <em>v</em>₀ <em>t</em> - 1/2 <em>g</em> <em>t</em> ²

and

<em>v</em> = <em>v</em>₀ - <em>g t</em>

where <em>v</em>₀ is its initial speed and <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.

The ball is falling with a velocity of 7.94 m/s when it's 2.72 m below the release point, which at time <em>t </em>such that

-2.72 m = <em>v</em>₀ <em>t</em> - 1/2 <em>g</em> <em>t</em> ²

-7.94 m/s = <em>v</em>₀ - <em>g t</em>

Solve for <em>t</em> in the second equation:

<em>t </em>= (<em>v</em>₀ + 7.94 m/s)/<em>g</em>

Substitute this into the first equation and solve for <em>v</em>₀ :

-2.72 m = <em>v</em>₀ (<em>v</em>₀ + 7.94 m/s) /<em>g</em> - 1/2 <em>g</em> ((<em>v</em>₀ + 7.94 m/s)/<em>g</em>)²

-2.72 m = <em>v</em>₀²/<em>g</em> + (7.94 m/s) <em>v</em>₀/<em>g</em> - 1/2 (<em>v</em>₀ + 7.94 m/s)²/<em>g</em>

2 (-2.72 m) <em>g</em> = 2<em>v</em>₀² + 2 (7.94 m/s) <em>v</em>₀ - (<em>v</em>₀ + 7.94 m/s)²

2 (-2.72 m) (9.80 m/s²) = 2<em>v</em>₀² + (15.9 m/s) <em>v</em>₀ - (<em>v</em>₀² + (15.9 m/s) <em>v</em>₀ + 63.0 m²/s²)

-53.3 m²/s² = <em>v</em>₀² - 63.0 m²/s²

<em>v</em>₀² = 9.73 m²/s²

<em>v</em>₀ = 3.12 m/s

3 0
2 years ago
Ocean breezes are due to which method of heat transfer?
Ber [7]
Ocean breezes are due to the convection method of heat transfer
8 0
2 years ago
Read 2 more answers
Charge g is distributed in a spherically symmetric ball of radius a. (a) Evaluate the average volume charge density p. (b) Now a
nasty-shy [4]

Answer:

Explanation:

The volume of a sphere is:

V = 4/3 * π * a^3

The volume charge density would then be:

p = Q/V

p = 3*Q/(4 * π * a^3)

If the charge density depends on the radius:

p = f(r) = k * r

I integrate the charge density in spherical coordinates. The charge density integrated in the whole volume is equal to total charge.

Q = \int\limits^{2*\pi}_0\int\limits^\pi_0  \int\limits^r_0 {k * r} \, dr * r*d\theta* r*d\phi

Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0  \int\limits^r_0 {r^3} \, dr * d\theta* d\phi

Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 {\frac{r^4}{4}} \, d\theta* d\phi

Q = k *\int\limits^{2*\pi}_0 {\frac{\pi r^4}{4}} \,  d\phi

Q = \frac{\pi^2 r^4}{2}}

Since p = k*r

Q = p*π^2*r^3 / 2

Then:

p(r) = 2*Q / (π^2*r^3)

3 0
2 years ago
Motor oil , with a viscosity of 0 . 250 Ns / m2 , is flowing through a tube that has a radius of 5 . 00 mm and is 25 . 0 cm long
Thepotemich [5.8K]

Answer:

1.1775 x 10^-3 m^3 /s

Explanation:

viscosity, η = 0.250 Ns/m^2

radius, r = 5 mm = 5 x 10^-3 m

length, l = 25 cm = 0.25 m

Pressure, P = 300 kPa = 300000 Pa

According to the Poisuellie's formula

Volume flow per unit time is

V=\frac{\pi \times Pr^{4}}{8\eta l}

V=\frac{3.14 \times 300000\times \left ( 5\times 10^{-3} \right )^{4}}{8\times 0.250\times 0.25}

V = 1.1775 x 10^-3 m^3 /s

Thus, the volume of oil flowing per second is 1.1775 x 10^-3 m^3 /s.

3 0
3 years ago
Other questions:
  • In Hooke's law, what does k represent?
    11·2 answers
  • What are balanced forces?
    15·2 answers
  • Two straight wires are in parallel and carry electrical currents in opposite directions with the same magnitude of LaTeX: 2.02.0
    15·1 answer
  • Who was the first who traveled to the moon?​
    8·2 answers
  • A filing cabinet weighing 556 N rests on the floor. The coefficient of static friction between it and the floor is 0.68, and the
    9·1 answer
  • Can you answer this question about work and force?
    6·1 answer
  • Is a balance scale used to describe how much matter is in an object
    7·2 answers
  • Force due to gravity. While JWST is in orbit, the Earth will be at a distance of 1.494 x 109 m from the telescope, and the Sun w
    14·1 answer
  • An oil droplet is levitated and held at rest in a region where the electric field is 1.4x104 N/C directed vertically downwards.
    7·1 answer
  • Answer This!!!!!!<br> I'll give brainliest to whoever gets it right.<br> And 100 Points!
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!