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galina1969 [7]
2 years ago
8

Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis. Part A What distance should one speaker be placed

behind the other for the sound to have an amplitude 1.50 times that of each speaker alone
Physics
1 answer:
Fiesta28 [93]2 years ago
7 0

The distance a speaker should be placed behind  other sound to have an amplitude 1.50 times is 4.523 m.

<h3>What is wavelength?</h3>

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = v/f

Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis.

λ  = 343 m/s /1000 Hz

λ = 0.343 m

Distance, one should speaker be placed behind the other for the sound to have an amplitude 1.50 times that of each speaker alone.

The amplitude of the waveform due to waves,

A = 2a cos (ΔΦ/2)

ΔΦ = 2π x Δx/λ

So, A =  2a cos (π x Δx/λ)

Substitute the values, we get

1.5a = 2a cos (3.14 x  Δx/ 0.343)

Δx = 4.523 m

Thus, the distance is 4.523 m.

Learn more about wavelength.

brainly.com/question/13533093

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