A. it will eventually reach its carrying capacity
Answer:
3212
Explanation:
Transport vesicles are vesicles that function to carry molecules from one cellular compartment to another. The coat protein complexes I and II (COPI and COPII) are conserved pathways that transport proteins from the endoplasmic reticulum to the Golgi apparatus. Moreover, clathrin is a protein implicated in the formation of coated vesicles. The ADP-ribosylation factor GTPase activating (Arf GAP) proteins play a major role in Arf signaling pathways, which are responsible for uncoating of the COPI coat. On the other hand, COPII vesicles are known to retain their coats until they are recognized by tethering complexes, and whose formation is regulated by the GDP-GTP cycle of the small GTPase Sar1. Finally, the 70-kDa heat shock proteins (HSP70) are chaperones which function as uncoating ATPases to remove clathrin from coated vesicles after endocytosis.
NaCl is dissolved in water so that in a given region or volume the concentration is initially higher in one part than the other l, thus simple diffusion will occur so that there is a net difference or 0, with respect to the concentration of NaCl in a particular volume of water than another. Basically the NaCl will be distributed throughout volume of water.
In the story and according to Scrooge, the place were poor people work to get their food is the workhouse. It is also the place where Scrooge things poor people must spend their Christmas. Aside from this, he also said that the prison is also a place for poor people during Christmas.
Answer:
(a) number of strands (n) = time (t) ÷ proportionality constant (k)
(b) The time needed for the bacterial to double its initial size is 3.36 hours.
Explanation:
(a) Let the rate (time) be represented by t and the amount (number) of strands of bacteria be represented by n
t is proportional to n, therefore, t = kn (k is the proportionality constant)
Since t = kn, then, n = t/k
(b) Initial amount of strands = 300
Amount of strands after 2 hours = 300 + (300 × 20/100) = 300 + 60 = 360
k = t/n = 2/360 = 0.0056 hour/strand
Double of the initial size is 600 (300×2 = 600)
Time (t) needed for the bacterial to double its initial size = kn = 0.0056×600 = 3.36 hours
