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Musya8 [376]
2 years ago
7

Lin cooked a pot of soup, then put half the soup in the freezer for a while. Now the soup in the pot is hot, and the soup in the

freezer is cold. What is the difference between the molecules of the soup in the pot and the molecules of the soup in the freezer?
Mathematics
2 answers:
maria [59]2 years ago
7 0

Answer:

The molecules of the soup in the freezer are very slow as for the soup in the pot the molecules are moving fast

Mark me brainliest plz ;)

DiKsa [7]2 years ago
4 0

Answer:

The molecules in the freezer are rearranged into a different pattern, the molecules have not changed

pls mark me as branliest :D ;)

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Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

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Answer:

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Step-by-step explanation:


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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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