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amm1812
3 years ago
11

Dr. Smith gives his staff a 1/3 bonus if they exceed the quarterly goal. This extended this quarter they exceeded the goal by 15

00. what is the staff bonus for this quarter?
Mathematics
1 answer:
Neporo4naja [7]3 years ago
3 0
<span>As they exceed the goal by 1500 and the bonus is 1/3 of the exceed then they will receive 1500 * 1/3 = 500 The staff bonus for this quarter is 500</span>
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amm1812

Answer:

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Step-by-step explanation:

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6 0
3 years ago
The difference of two numbers is 15. Five times the smaller is the same as 9 less than twice the larger. Find the numbers
Usimov [2.4K]

Answer:

x= -13

y= -28

Step-by-step explanation:

To find the two numbers, write a system of equations with x as one number and y as another:

x-y=15

5x=2y-9

Use substitution to substitute one equation into another. Then solve for the variable.

x=15+y into 5x=2y-9

becomes

5(15+y) = 2y-9

75+5y = 2y- 9

75+3y= -9

3y = -84

y= -28

To find x, substitute y= -28 into one equation.

x - (-28) = 15

x+28 =15

x = 15-28

x=-13




6 0
3 years ago
How many faces does a square pyramid have? three four five six
andrew-mc [135]

Answer:

5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the value of the y-intercept of the line 7x-4y=20?<br> 7/4<br> 5<br> -5
USPshnik [31]

Answer:

-5

Step-by-step explanation:

Once you get y alone the equation will look like this y=-7/4x-5.

The slope intercept form dictates that y=mx+b, with b being the y-intercept, so -5 is b, therefore the y intercept.

3 0
3 years ago
Jacob and issac decided to run to the basketball court after school the basketball court is 5 1/4 Miles from school the boys run
GenaCL600 [577]

Answer: 1\dfrac{5}{9}\text{ minutes}

Step-by-step explanation:

Complete question is provided in the attachment below.

Given: Jacob and Issac decided to run to the basketball court

Distance between basketball court and school = 5\dfrac{1}{4} miles

=\dfrac{21}{4} miles

Speed = 3\dfrac{3}{8} miles per hour

=\dfrac{27}{8} miles per hour

Since, time = (distance) ÷ ( speed)

Now, the time taken by boys to arrive at the basketball court = \dfrac{21}{4}\div\dfrac{27}{8} hours

=\dfrac{21}{4}\times\dfrac{8}{27}\\\\=\dfrac{7\times2}{9}=\dfrac{14}{9}\\\\=1\dfrac{5}{9}\text{ minutes}

Hence, the required length of time = 1\dfrac{5}{9}\text{ minutes}

3 0
3 years ago
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