The triangle has sides a,b,c such that
a = 2*sqrt(5), b = sqrt(5), and c = 2*sqrt(10)
Square each value
a = 2*sqrt(5)
a^2 = (2*sqrt(5))^2
a^2 = 2^2(sqrt(5))^2
a^2 = 4*5
a^2 = 20
b^2 = 20 for similar reasons as side 'a'
c = 2*sqrt(10)
c^2 = (2*sqrt(10))^2
c^2 = 2^2*(sqrt(10))^2
c^2 = 4*10
c^2 = 40
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Using the pythagorean theorem, we see that
a^2 + b^2 = c^2
20 + 20 = 40
40 = 40
So the initial equation a^2 + b^2 = c^2 is true making the triangle with sides a,b,c defined above to be a right triangle
f(x) = 3x - 1
g(x) = 2x - 3
g(x) = f(2)
g(x) = 3.2 - 1
g(x) = 6 - 1
g(x) = 5
If g(x) = 5, then, 2x - 3 = 5
2x - 3 = 5
2x = 5 + 3
2x = 8
x = 8/2
x = 4
So,
f(2) = g(4)
Answer:
3x would equal 18 is x was 6
Step-by-step explanation:
x=6
3*6=18
3x would equal 18
