All categories

2 years ago

Solve the inequality. a−2>4

Mathematics

2 answers:

Sunny_sXe [5.5K]2 years ago

5 0

The answer is A>6 i just copied the guy

Ghella [55]2 years ago

4 0

Answer:

a>6

Step-by-step explanation:

You might be interested in

Given the system of equations, what is the y-coordinate of the solution?5x - 4y = 7x = 5 - y

sveticcg [70]

5x - 4y = 7
x = 5 - y

5(5 - y) - 4y = 7
25 - 5y - 4y = 7
-5y - 4y = 7 - 25
-9y = - 18
y = -18/-9
y = 2 <== y coordinate is 2

6 0

3 years ago

Solve each system of equations below by substitution

Anna007 [38]

Answer:

numero uno, ok

Step-by-step explanation:

6 0

3 years ago

I need help with this homework to practice for a quiz may you please help me ?

laiz [17]

Answer:

set the equations equal to each other, the equations are equal. then find value of x

Step-by-step explanation:

5x+17=3x-4

solve from here

hope this helped boo;p

5 0

3 years ago

The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th

insens350 [35]

Answer: a = 8; b = 15; c = 17

Step-by-step explanation:

c = b + 2 and c = 2a + 1

b = c − 2 and a = $\frac{c-1}{2}$

c² = b² + a²

$c^{2} = (c-2)^{2} + \frac{c-1}{2}\\$

$c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2} }{4}$

$4c^{2}={4 (c^{2} + 4 -4c)+c ^{2} + 1-2c$

$4c^{2}={4 c^{2} + 16 -16c)+c ^{2} + 1-2c$

$c^{2}-18c+17=0$

$c(c -17)-1(c-17)=0$

$(c -1)(c-17)=0$

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = $\frac{17-1}{2} = 8$

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

$a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\$

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0

3 years ago

Identify the value of p. Give your answers in simplest radical form. HELP PLEASE!!

VikaD [51]

Answer:

Step-by-step explanation:

using the cosine ratio to find p

cos 45° = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{p}$

cross- multiplying gives

p × cos45° = 6 → [ cos 45° = $\frac{1}{\sqrt{2} }$ ]

p × $\frac{1}{\sqrt{2} }$ = 6

multiply both sides by $\sqrt{2}$

⇒ p = 6 $\sqrt{2}$ ( third option on list )

7 0

3 years ago