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tigry1 [53]
2 years ago
8

Solve the inequality. a−2>4

Mathematics
2 answers:
Sunny_sXe [5.5K]2 years ago
5 0
The answer is A>6 i just copied the guy
Ghella [55]2 years ago
4 0

Answer:

a>6

Step-by-step explanation:

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Mark has a jar of marbles. The jar contains 1 red marble, 2 green marbles, 15 yellow marbles, and 11 blue marbles. Without looki
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3 years ago
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WILL MARK YOU BRAINLIEST
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the answer is 3/2

Step-by-step explanation:

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3 years ago
Are the following lines parallel? <br><br> y = -3x + 1 <br><br> y = 4 - 3x
PIT_PIT [208]

Answer:

Simple! The answer is yes.

Step-by-step explanation:

Simply put the equations into Desmos graphing calculator and it will show you that the equations are parallel. :))

4 0
2 years ago
1. Which of the following is NOT true about an isosceles trapezoid?
viktelen [127]
On an isosceles trapezoid, the two sides that are not parallel to each other will be exactly the same length.  If this is true, than it would be create a symetric trapezoid.  The diagonals would be the same length.  The bases of any trapezoid are parallel, so this is true.  The diagonals cannot possibly be perpendicular because the 2 nonparallel sides would be slanted.  So, the answer is the 3rd choice.
5 0
3 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
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