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Damm [24]
2 years ago
13

This is slightly urgent. Does anyone know how to cross multiply and divide 1/5 and 20/x? It would look like this if you need the

equation.
1/5 * 20/x​
Mathematics
1 answer:
kumpel [21]2 years ago
6 0

Answer:

1/5 * 20/x. first do 1× x then do 5×20 and you will get 1x/100

Step-by-step explanation:

sorry this is all i know

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This question so hard pls helps
Nesterboy [21]

Answer:

x . 2 = y

Step-by-step explanation:

What's the question..like what are the instructions

8 0
3 years ago
A single chocolate muffin has 260 calories, and a blueberry muffin has 240 calories. Both muffins can be bought at the local caf
Stella [2.4K]

Answer:

364 calories

Step-by-step explanation:

1/2 of 240=120 calories

fruit platter =210 calories

1/3 of 102=34

120+210+34=364 calories

8 0
3 years ago
Someone help me<br>10-14x-7-7x=6​
Burka [1]

Answer: your answer is going to be 1/7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help it is due ASAP....
melomori [17]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
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~**Will mark brainliest **~<br> For the correct answers to all three questions
aleksandr82 [10.1K]

a)

\dfrac{42}{65}\cdot\dfrac{25}{36}\cdot\dfrac{26}{49}=\dfrac{2\cdot3\cdot7}{5\cdot13}\cdot\dfrac{5\cdot5}{2\cdot2\cdot3\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\dfrac{7}{13}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\\\\\\=\dfrac{1}{1}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{1}{7}=\dfrac{5}{21}

b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

6 0
3 years ago
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