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podryga [215]
3 years ago
8

15. A T-shirt company charges $4.25 to create the design for a T-shirt and $9.25 per

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0
To solve this, i suggest coming up with an equation. Let “C” represent cost of production, and “x” represent number of shirts ordered.

C = 9.25x + 4.25

Since C is $87.50, plug that value in and find x.

87.5 = 9.25x + 4.25
83.25 = 9.25x
9 = x

Therefore, Diego ordered 9 shirts. I hope this helps.
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kiruha [24]

Answer:

that's

Step-by-step explanation:

+4y -12 thank you

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Find the area of the regular polygon below. leave your answer in simplest radical form.
Licemer1 [7]

Answer:

384√3 in²

Step-by-step explanation:

Given in the question a regular 6 sided polygon

To find it's area you have to use the following formula

<h3>      1/2 x perimeter x apothem</h3>

<em>Perimeter = the sum of the lengths of all the sides </em>

<em>Suppose length of one side = x</em>

<em>Apothem = a segment that joins the polygon's centre to the midpoint of any side that is perpendicular to that side = 8√3</em>

<em />

Since the polygon have 6 sides so

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plug values in the formula of area

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6 0
4 years ago
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Cos pi/4 cos pi/6= 1/2(___pi/12+cos 5pi/12) fill in the blank
inessss [21]

Answer:

\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{12})+\cos(\frac{5\pi}{12}))

So the blank is cos.

Step-by-step explanation:

There is an identity for this:

\cos(a)\cos(b)=\frac{1}{2}(\cos(a+b)+\cos(a-b))

Let's see if this is fit by your left hand and right hand side:

So a=\frac{\pi}{4} while b=\frac{pi}{6}.

Let's plug these in to the identity above:

\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{4}+\frac{\pi}{6})+\cos(\frac{\pi}{4}-\frac{\pi}{6}))

Ok, we definitely have the left hand sides are the same.

Let's see if the right hand sides are the same.

Before we move on let's see if we can find the sum and difference of \frac{\pi}{4} and \frac{\pi}{6}.

We will need a common denominator.  How about 12? 12 works because 4 and 6 go into 12.  That is 4(3)=12 and 6(2)=12.

\frac{\pi}{4}+\frac{\pi}{6}=\frac{3\pi}{12}+\frac{2\pi}{12}=\frac{5\pi}{12}.

\frac{\pi}{4}-\frac{\pi}{6}=\frac{3\pi}{12}-\frac{2\pi}{12}=\frac{\pi}{12}.

Let's go back to our identity now:

\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{4}+\frac{\pi}{6})+\cos(\frac{\pi}{4}-\frac{\pi}{6}))

\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{5\pi}{12})+\cos(\frac{\pi}{12}))

We can rearrange the right hand side inside the ( ) using commutative property of addition:

\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{12})+\cos(\frac{5\pi}{12}))

So comparing my left hand side to their left hand side we see that the blank should be cos.

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3 years ago
Help me i need it
Fofino [41]

Answer:

there too much lol I have no clue

Step-by-step explanation:

hop I help not really but yeah

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