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Ray Of Light [21]
3 years ago
6

Maria received a $90 gift card for a coffee store. She used in buying some coffee that costs $7.81 per pound. After buying the c

offee, she had $50.95 left on her card. How many pounds of coffee did she buy?
Mathematics
2 answers:
lidiya [134]3 years ago
6 0

Answer:

5 pounds

Step-by-step explanation:

Because we are already given the unit rate in money per pound (money/pound), and we must determine the quantity, we must rearange the equation for rate to solve for the quantity we are looking for. Since in this problem, the rate = change in money / change in pounds. This done by first subtracting the money on the gift card from the money remaining to determine the change in money. Then divide this by the rate of $7.81 (money per pound) to cancel out the money and get the pounds of coffee.

So:

rate (in this case, $7.81 per pound) = change in money / change in pounds →

change in pounds = change in money / rate ($7.81 per pound)

Therefore:

change in pounds = $90 - $50.95 / $7.81 =

$39.05 / $7.81 = 5

sergiy2304 [10]3 years ago
5 0

Answer:

Im not sure but im going to try

Step-by-step explanation:

First you subtract $7.81 from $90 until you get to $50.95 and then you count how many times you subtract and your answer is 5 pounds of coffee.

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What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
uysha [10]

Answer:

The perimeter of the trapezoid is 38.25\ units

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

P=QR+RS+ST+QT

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

Q(8, 8), R(14, 16), S(20, 16),T(22, 8)

step 1

Find the distance QR

Q(8, 8), R(14, 16)

substitute the values in the formula

d=\sqrt{(16-8)^{2}+(14-8)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

QR=10\ units

step 2

Find the distance RS

R(14, 16), S(20, 16)

substitute the values in the formula

d=\sqrt{(16-16)^{2}+(20-14)^{2}}

d=\sqrt{(0)^{2}+(6)^{2}}

d=\sqrt{36}

RS=6\ units

step 3

Find the distance ST

S(20, 16),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-16)^{2}+(22-20)^{2}}

d=\sqrt{(-8)^{2}+(2)^{2}}

d=\sqrt{68}

ST=8.25\ units

step 4

Find the distance QT

Q(8, 8),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-8)^{2}+(22-8)^{2}}

d=\sqrt{(0)^{2}+(14)^{2}}

d=\sqrt{196}

QT=14\ units

step 5

Find the perimeter

P=10+6+8.25+14=38.25\ units

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