Answer:
The smallest positive integer solution to the given system of congruences is 30.
Step-by-step explanation:
The given system of congruences is
where, m and n are positive integers.
It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as
Now, we can say that m>n because m and n are positive integers.
For n=1,
19 is not divisible by 5 so m is not an integer for n=1.
For n=2,
The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is
Therefore the smallest positive integer solution to the given system of congruences is 30.
The answer is D.
We know that a rectangle has two widths that are equal and two lengths that are equal. One width is 22, so the other one is also 22.
If you wanted to find the lengths, you would add both widths together (same as multiplying a width by two) and add that to the two lengths equaled to the perimeter.
So, 22 * 2 + 2x = perimeter of rectangle. We added all four sides together.
We know that the perimeter is at least 165, so 22 * 2 + 2x = 165. Here's the twist. They want the most minimum possible length. So, what answer choice gives you 165 or less for the most minimum or smallest length while still getting to 165?
That is D.
22 * 2 + 2x < = 165.
Hope this helped!
Answer:
D
Step-by-step explanation:
Plug in every scenario, in see if it equal to each other.
D is the only one that is equal.
Need to know the angle for this I think?
