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Vinil7 [7]
2 years ago
6

Please help me please will give brainliest to anyone ​

Mathematics
1 answer:
aliina [53]2 years ago
6 0

Answer:

<h2>c.</h2>

Step-by-step explanation:

>means the unit rate once of icing for cake

=40 4/5 ounces

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What is 8/21 in simplest form
Liono4ka [1.6K]
It is already in simplest form
Hope this helps you!
6 0
3 years ago
What is the solution to the system of equations? One-fourth x minus one-half y = 8 One-half x + three-fourths y = negative 5 (–8
kiruha [24]

Answer:

Step-by-step explanation:

x/4-y/2=8, x-2y=32, x=32+2y

x/2+3y/4=-5, 2x+3y=-20, x=(-20-3y)/2

32+2y=(-20-3y)/2

64+4y=-20-3y

7y=-84

y=-12, since x=32+2y

x=32+2(-12), x=32-24=8

So the solution is the point (8, -12)

3 0
3 years ago
Read 2 more answers
(4x + 2), (2x +3), and (x-2)
Lena [83]
The answer is 7x-3 if you add like terms which are 4x, 2x, and x then take 2, 3, -2 and subtract from each other
4 0
2 years ago
Read 2 more answers
An education researcher claims that 58​% of college students work​ year-round. In a random sample of 400 college​ students, 232
Hatshy [7]

Answer:

The proportion of college students who work​ year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58​% of college students work​ year-round.

A random sample of 400 college​ students, 232 say they work​ year-round.

To test the researcher's claim use a one-proportion <em>z</em>-test.

The hypothesis can be defined as follows:

<em>H</em>₀: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> = 0.58.

<em>Hₐ</em>: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> ≠ 0.58. C

Compute the sample proportion as follows:

 \hat p=\frac{232}{400}=0.58

Compute the test statistic value as follows:

 z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

 p-value=2\times P(z

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work​ year-round is 58%.

6 0
3 years ago
Add.
Vikki [24]

Answer:

5/6

Step-by-step explanation:

9/30 + 16/30 = 25/30 = 5/6

3 0
3 years ago
Read 2 more answers
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