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2 years ago

Please help me please will give brainliest to anyone

Mathematics

1 answer:

aliina [53]2 years ago

6 0

Answer:

Step-by-step explanation:

>means the unit rate once of icing for cake

=40 4/5 ounces

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What are all values of x for which the series shown converges?

adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

$\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}$

We can write this as:

$\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}$

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

$\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}$

Then we have the inequality

$1 > (x - 2)/3$

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0

2 years ago

What are the odds against choosing a red marble from a bag that contains two blue marbles, one green marble, seven white marbles

Alina [70]

Answer:

4/14

Step-by-step explanation:

2+1+7+4=14

red marbles are 4/14

7 0

2 years ago

Read 2 more answers

Plssss Help!!! Will mark brainiest!!

marshall27 [118]

Answer:

the last one

Step-by-step explanation:

5 0

3 years ago

Miranda wants to go to her school's Prom night.A ticket costs $110. She has $50 saved, however, to earn the rest she is going to

Alex73 [517]

Answer:

110=50+7(x)

Step-by-step explanation:

6 0

3 years ago

A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are

Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

$P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764$