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4 years ago

35-14 ÷ 2+8^2 PLEASE SHOW WORK

Mathematics

1 answer:

umka2103 [35]4 years ago

8 0

Do order of operations for this problem.
35-14/2+8^2
35-14/2+64
35-7+64
35+57=92

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a regular pentagon-based pyramid has 5 faces which are equilateral triangles the perimeter of it's net is 70cm what is the perim

netineya [11]

Answer:

35cm

Step-by-step explanation:

The net of a regular pentagon has 10 sides.

Since each of the faces are equilateral triangles, the side lengths are equal.

Therefore:

Length of each side of the net = 70/10 =7cm

Therefore, the base is a regular pentagon of side length 7cm.

The perimeter of the base of the pyramid = 5 X 7

=35cm

The perimeter of the base of the pyramid is 35cm.

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4 years ago

Write five pairs of integers (a, b) such that a÷b equals to - 6

Volgvan

Answer:

(-6,1) (-12,2) (-18,3) (-24,4) (-30,5)

Hope this helps!

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3 years ago

The original sale price of an item at markdowns is $110.95. You have an additional 20% off coupon for markdowns for purchases to

IRINA_888 [86]

Answer:

$22.19

Step-by-step explanation:

20% off the original price = $110.95 - (20% x $110.95)

20% x $110.95 = $22.19

$110.95 - $22.19 = $88.76

difference = $110.95 - $88.76 = $22.19

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3 years ago

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dlinn [17]

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3 years ago

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Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago