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ollegr [7]
3 years ago
5

Solve for x. 9 <17 - 4.0 Enter your answer, as an inequality, in the box.

Mathematics
1 answer:
Rashid [163]3 years ago
6 0

9 <= 17 -4x

Subtract t 17 from both sides:

-8 <= -4x

Divide both sides by-4,

2 <= x

Rewrite the inequality with the x on the left side.

Answer: x <=2

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The point (0, 0) is a solution to which of these inequalities?
strojnjashka [21]

The point (0, 0) is a solution to which of these inequalities are satisfied. so option B. y-7<2x-6is the only correct answer.

<h3>What is inequality?</h3>

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

The point (0, 0) is a solution to which of these inequalities are satisfied.

A. y+7<2x - 6

      7 < -6

So, it is incorrect.

B. y-7<2x-6

      -7 < -6

So, it is correct.

C. y-6<2x-7

         -6 < -7

So, it is incorrect.

D. y+7<2x+6

7 < 6

So, it is incorrect.

Hence, option B is the only correct answer.

Learn more about inequality ;

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3 years ago
Write yes or no equation in standard form
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yes equation in standard form of advertising with a room stream NY

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Goryan [66]

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the answer is 20

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Consider the function f(x)=2x-1. Whats is f(2)
xz_007 [3.2K]
The answer is 3.
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8 0
3 years ago
A construction company employs two sales engineers. Engineer 1 does the work of estimating cost for 70% of jobs bid by the compa
netineya [11]

Answer:

Engineer 1

Step-by-step explanation:

Based on the information given:

P( 1 ) = 0.7

P( 2 ) = 0.3

P(A | B) is a conditional probability: the likelihood of event A occurring given that B is true.

P( E | 1 ) = 0.02

P( E | 2 ) = 0.04

Then P( E | 1 ) is the probability that an error occurs when engineer 1 does the work and P( E | 2 ) is the probability that an error occurs when engineer 2 does the work.

To have an idea of which engineer is more likely to do the work when an error occurs you need to calculate P( 1 | E ) and P( 2 | E ), The probability that engineer 1 does the work when an error occurs and the probability that engineer 2 does the work when an error occurs.

The Bayes's theorem states:

P( B | A ) = \frac{P( A | B )*P( A )}{P( B )}

Using the notation above:

P( 1 | E ) = \frac{P( E | 1 )*P( 1 )}{P( E )}

P( E ) = 0.7*0.02 + 0.3*0.04 = 0.026 /// the probability that engineer 1 does the work and an error occurs or the probability that engineer 2 does the work and an error ocurrs.

P( 1 | E ) = \frac{0.04*0.3}{0.026}=0.538

Doing the same for engineer 2:

P( 2 | E ) = \frac{0.04*0.3}{0.026}=0.462

6 0
3 years ago
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