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3 years ago

Which characteristic(s) makes a compounds useful as a building material?

Chemistry

1 answer:

Semenov [28]3 years ago

3 0

Answer:

The answer is hardness and brittleness. The ion discharging procedure and taking after impact on reservoir water quality file, for example, hardness, pH, conductivity, has been dissected. Comes about uncovered that the most discharge quality of various materials was touching base at the 30s after startup.

Explanation:

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Which identifies an oxidation-reduction reaction? a double replacement reaction a neutralization reaction a reaction in which ox

OLga [1]

A reaction in which oxidation numbers change is the answer! :D

☆ Dont forget to mark brainliest ☆

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4 years ago

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Sulfur trioxide is a gas that reacts with liquid water to produce aqueous sulfuric acid, or acid rain. What is the equation for

BartSMP [9]

SO3+H2O-->H2SO4
If you need their states
SO3(g) + H2O(l) --> H2SO4(aq)
And they're already balanced

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3 years ago

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A chemist dissolves 484 .mg of pure perchloric acid in enough water to make up 240.mL of solution. Calculate the pH of the solut

sdas [7]

Answer:

1.70

Explanation:

The molar mass of perchloric acid is 100.46 g/mol. The moles corresponding to 484 mg (0.484 g) are:

0.484 g × (1 mol/100.46 g) = 4.82 × 10⁻³ mol

4.82 × 10⁻³ moles are dissolved in 240 mL (0.240 L) of solution. The molar concentration of perchloric acid is:

4.82 × 10⁻³ mol/0.240 L = 0.0201 M

Perchloric acid is a strong monoprotic acid, that is, it dissociates completely, so [H⁺] = 0.0201 M.

The pH is:

pH = -log [H⁺] = -log 0.0201 = 1.70

8 0

3 years ago

Select the compound in which chlorine is assigned the oxidation number +5

IrinaK [193]

Answer:

The answer is NaClO3

5 0

3 years ago

How many molecules of carbon monoxide gas can be produced from 395 grams of oxygen gas ?

puteri [66]

The answer for the following problem is mentioned below.

Therefore 148.125 × 10^-23 molecules of the cabon monoxide gas is produced.

Explanation:

Given:

mass of the oxygen gas = 395 grams

We know;

For the production of the carbon monoxide;

The equation is,

Before balancing the equation;

C + $O_{2}$ → CO

After balancing the equation;

2 C + $O_{2}$ → 2 CO

where,

C = carbon molecule

O = oxygen molecule

CO = carbon monoxide

For the equation,

32 grams of oxygen gas → 2 × 6.023 × 10^-23 molecules

395 grams of oxygen gas → ?

= $\frac{2*6.023*10^{-23}* 395}{32}$

= 148.125 × 10^-23 molecules of the carbon monoxide

Therefore 148.125 × 10^-23 molecules of the cabon monoxide gas is produced.

3 0

4 years ago