Answer:
The answer to your question is V2 = 29.6 l
Explanation:
Data
Pressure 1 = P1 = 12 atm
Volume 1 = V1 = 23 l
Temperature 1 = T1 = 200 °K
Pressure 2 = 14 atm
Volume 2 = V2 = =
Temperature 2 = T2 = 300°K
Process
1.- To solve this problem use the Combine gas law.
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
2.- Substitution
V2 = (12)(23)(300) / (200)(14)
3.- Simplification
V2 = 82800 / 2800
4.- Result
V2 = 29.6 l
Answer:
Given: 42 g of N2
Solve for O2 mass that contains the same number of molecules to 42 g of N2.
Solve for the number of moles in 42 g of N2
1 mole of N2 = (14 * 2) g = 28 g so the number of moles in 42 g of N2 is equal to 42 g / 28 g per mole = 1.5 moles
Solve for mass of 1 mole of oxygen
1 mole of O2 = 16 g * 2 = 32 g per mole
Solve for the mass of 1.5 moles of oxygen
mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles
mass of 1.5 moles of O2 = 48 g
So 48 g of O2 contains the same number of molecules as 42 g of N2
Answer:

This is a double displacement reaction, C goes with Cl in the products side and O2 goes with H. All that is left is to balance the equation, making sure each side has equal amounts of atoms.
The most electronegative element will have atoms with strongest association for electrons. Electronegativity is the ability of an atom to attract electrons and form bonds with electrons. . In the periodic table the left hand side favors the loss of electrons because less energy is required to lose an electron than to gain an electron. On the other han, the right hand side favors gaining electrons since less energy is required than when losing electrons.
Henceforth, from left to right in the periodic table the tendency to gain electrons increases. In contrast, going down a group there is decreased association for electrons, because atomic radius increases which suggests that valence electrons are further away from the nucleus.This makes fluoride the ion with strongest association of electrons. The noble gases have a complete shell so cannot attract electrons to themselves, which means they have no electronegativity.