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3 years ago

What is the law of redox reactions?

Chemistry

1 answer:

lbvjy [14]3 years ago

6 0

Answer:

. All redox reactions occur with a simultaneous change in the oxidation numbers of some atoms. At least two elements must change their oxidation numbers. When an oxidation number of an atom is increased in the course of a redox reaction, that atom is being oxidized

Explanation:

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Suppose the reaction system below has already reached equilibrium. Predict the effect that each of the following changes will ha

WARRIOR [948]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On removal of reactant from equilibrium reaction ,shifts the equilibrium in backward direction.
On addition of reactant from equilibrium reaction ,shifts the equilibrium in forward direction.
On removal of product from equilibrium reaction, shifts the equilibrium in forward direction.
On addition of product from equilibrium reaction, shifts the equilibrium in backward direction.

$UO_2(s) + 4 HF(g)\rightleftharpoons UF_4(g) + 2 H_2O(g)$

1. Water vapor is removed

On removal of water vapor from equilibrium will decrease the product which will lead to moving forward of an equilibrium that is equilibrium will shift to right direction.

2. $UF_4(g)$ is added

On addition of $UF_4(g)$ from equilibrium will increase the reactant which will lead to moving forward of an equilibrium that is equilibrium will shift to right direction.

3.The reaction is done in a glass reaction vessel. HF(g) attacks and reacts with the glass

Due to reaction of HF with glass will result in decrease in amount of HF present at equilibrium. So, order to counter this equilibrium will shift in backward direction or in left direction.

4. If the reaction is endothermic, and you want to make the equilibrium shift to the right to maximize the products, would you heat or cool the reaction vessel.

I endothermic reaction , heat is added to the reaction for which we can treat heat as a reactant.Now, we want to shift the equilibrium to right which means in the forward direction.

And this can be done by increasing the reactant amount, here by adding more heat to the equilibrium will shift the reaction to the right side.

So, for increasing heat we will heat the reaction vessel.

5 0

3 years ago

When a sample of rust was mixed with acid, the rust changed into two simpler substances: W and Z. The substances W and Z could n

julia-pushkina [17]

here can be a number of chemical processes by which a compounds can be broken down into simpler substances. The most common and wide-spread of such processes is Catabolism. Along with anabolism, catabolism make up the metabolism process for living organisms. In catabolism, complex chemical molecules (such as proteins, polysaccharides, etc.) are broken down into simpler molecules (such as amino acids, monosaccharides, etc.). This is often accompanied by release of energy in the form of ATP (adenosine triphosphate) molecules and intermediate metabolites (which can be used by the organism in the anabolic processes). The energy thus generated is used for operation and maintenance of cells (and consequently, the body).

Other processes that break down chemical substances into simpler substances, include depolymerization, decomposition, etc.

Hope this helps.

6 0

3 years ago

Read 2 more answers

What one is correct?

katen-ka-za [31]

Explanation:

I am not positive but it makes more sense

7 0

3 years ago

Hydrogen and helium in the universe were formed by which of these phenomena?

baherus [9]

I think the answer is a

5 0

3 years ago

Acetic acid (CH3COOH) is a weak acid that partially dissociates in water. Given the reaction CH3COOH(aq) ↔ CH3COO−(aq) + H+(aq)

likoan [24]

Answer:

The correct answer is: 1.035 x 10⁻³ M

Explanation:

The dissociation equilibrium for acetic acid (CH₃COOH) is the following:

CH₃COOH(aq) ↔ CH₃COO⁻(aq) + H⁺(aq) Kc = 1.8 x 10⁻⁵

The expression for the equilibrium constant (Kc) is the ratio of concentrations of products over reactants. The products are acetate ion (CH₃COO⁻) and hydrogen ion (H⁺) while the reactant is acetic acid (CH₃COOH):

$Kc=\frac{[CH_{3} COO^{-} ][H^{+} ]}{[CH_{3} COOH]}= 1.8 x 10^{-5}$

Given: [CH₃COOH]= 0.016 M and [CH₃COO⁻]= 0.92 M, we replace the concentrations in the equilibrium expression and we calculate [H⁺]:

$\frac{(0.016 M)[H^{+} ]}{(0.92M)}= 1.8 x 10^{-5}$

⇒[H⁺]= (1.8 x 10⁻⁵)(0.92 M)/(0.016 M)= 1.035 x 10⁻³ M

8 0

3 years ago