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Lyrx [107]
2 years ago
12

6.9 moles of oxygen gas in a fixed volume of 1.33 liters. One of the valves opened and there remains only 1.24 moles oxygen gas.

What is the new volume of the gas
Chemistry
1 answer:
Romashka [77]2 years ago
7 0

Answer:

The new volume of the gas remains the same. That is new volume of gas is 1.33 litres

Explanation:

This is because gases do not have a definite shape. They therefore take the shape of their containing vessels and hence their volumes are determined by the volume of the container.

For the question above even if some of the gas escapes, as long as there is gas present in the container, its volume remains the same, that is occupies the same space in the container

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Compound X has a molar mass of 266.64 g/mol and the following composition: aluminum 20.24% chlorine 79.76% Write the molecular f
N76 [4]

Answer:

Explanation:

Assume we have 100g of this substance. That means we would have 20.24g of Cl and 79.76g of Al. Now we can find how many moles of each we have:

\frac{79.76 \:g}{35.45 \: g/mol} = 2.25 mol of chlorine

\frac{20.24 \: g}{26.98 \: g/mol} = 0.750 mol of Al.

To form a integer ratio, do 2.25/0.75 = 2.99999 ~= 3.

So the ratio is essentially Al : Cl => 1 : 3. To the compound is possibly AlCl_3.

However, it says it has a molar mass of 266.64 g/mol, and since AlCl3 has a molar mass of 133.32, it must be Al_2Cl_6.

Actually this molecule isn't exactly AlCl3 (which is ionic). Al2Cl6 forms a banana bond where Cl acts as a hapto-2 ligand. But that's a bit advanced. All you need to know is X = Al2Cl6

5 0
3 years ago
A Punnett square without the genotypes of the parents is shown below.
hammer [34]

Answer:

Genotype of parents is CC and Cc

Explanation:

Please see the attachment

8 0
3 years ago
5)
Karolina [17]
I believe it is b electric energy etc...
7 0
3 years ago
Explain why the molar ratio is needed to determine the theoretical mass ratios.
choli [55]

Answer:

The overview of the subject is outlined underneath in the summary tab.

Explanation:

  • The molar ratio seems to be essentially a balanced chemical equilibrium coefficient that implies or serves as a conversion factor for the product-related reactants.
  • This ratio just says the reactant proportion which reacts, but not the exact quantity of the reacting product. Consequently, the molar ratio should only be used to provide theoretical instead of just a definite mass ratio.

3 0
3 years ago
A student reduces the temperature of a 300 cm3 balloon from 60°c to 30°
FromTheMoon [43]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 303.15  x 300 / 333.15

<span>V2 = 272.99 cm³</span>

7 0
4 years ago
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