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3 years ago

.help me please thanks

Mathematics

1 answer:

larisa [96]3 years ago

4 0

The empty jug weighs 0.75 lb

With the 3c, the total weighs 2.25 lb. That means:

3c + empty jug = 3c + 0.75 = 2.25

3c = 2.25 - 0.75
3c = 1.5
and 1c = 0.5 (so c is a constant -or the slope-)

Then the equation is:

y = 0.5x + 0.75

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Round 763.53 to the nearest hundred

FinnZ [79.3K]

Answer:763.5

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Use logarithmic differentiation to find the derivative of the function. y = x2cos x Part 1 of 4 Using properties of logarithms,

Arisa [49]

ANSWER

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

EXPLANATION

The given function is

$y = {x}^{2} \cos(x)$

We take natural log of both sides;

$ln(y) = ln({x}^{2} \cos(x) )$

Recall and use the product rule of logarithms.

$ln(AB) = ln(A ) + ln(B)$

This implies that:

$ln(y) = ln({x}^{2} ) + ln( \cos(x) )$

$ln(y) = 2 ln({x} ) + ln( \cos(x) )$

We now differentiate implicitly to obtain;

$\frac{ {y}^{'} }{y} = \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) }$

Multiply through by y,

${y}^{'} = y( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) })$

Substitute y=x²cosx to obtain;

${y}^{'} = {x}^{2} \cos(x) ( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) } )$

Expand:

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

7 0

3 years ago

Plz help me my teacher has been gone on military leave and I'm totally lost

Degger [83]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~

The Domain: F

The Range: A

X-intercept: C

Y-intercept: D

the functional value: G

Increasing: B

Decreasing: E

Constant: H

6 0

3 years ago

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Hatshy [7]

-4 1/8 as decimal.
The decimal is -3.875.

7 0

3 years ago

If my radius is 10 feet, what is my diameter?

Anika [276]

Answer:

Your diameter would be 20.

Step-by-step explanation:

1. Two radius added together is the diameter (if you're talking about a circle.)

2. You add 10+10 because as you said your radius is 10.

3. It would be 20.

Hope this helped!

4 0

3 years ago