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jolli1 [7]
3 years ago
10

Please solve! add equation. Will Name Brainliest!!!!

Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0
A pack of bracelets were $1.20
marshall27 [118]3 years ago
5 0
Answer= $1.20

Step by step explanation-
7x+3x+2x=$14.40
12x=$14.40
x=14.40/12
x=$1.20
You might be interested in
if jacob used 1/7 of a liter of water to fill 1/9 of a fish aquarium how many liters are needed to fill the aquarium
Paladinen [302]
1/9 of the aquarium was filled with 1/7 liter

1 whole fraction  of the aquarium will be filled =    1/7 ÷ 1/9

                                                        = 1/7 * 9/1  = 9/7

   9/7 liters or 1   2/7 liters will be needed.    
6 0
4 years ago
Sapphire Island is open 7 days a week. The park has 8 ticket booths, and each booth has a ticket seller from 10:00am to 5pm. On
Oksanka [162]

Answer:  Hope this helps.

Step-by-step explanation:

8 0
4 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
..1+4=5. 2+5=12. 3+6=21. 8+11=40 or this could be 96 which is right and why
andre [41]
Multiply the numbers being added then add the first number. 4X1=4, 4+1=5.
2X5=10, 10+2=12. 11X8=88, 88+8=96. I'm not sure how to get 40, though. 
Hope I could help.
7 0
3 years ago
How to solve a quadratic equation when c=0
kherson [118]
Lets say we have a quadratic equation:

3x^2 + x + 0 = 0

Now, since if we add or subtract 0 from something, the original value stays the same, which means we can write the equation as 3x^2 + x = 0 and ignore the “+0”.

In these kinds of equations, you /can/ use the quadratic formula, but theres a much quicker way. If we factor 3x^2 + x, we get x(3x + 1) = 0. Here, x has two possible values — since the result of the multiplication is 0, that means that either one expression or the other must equal 0. In essence:

If x(3x+1) = 0 then x = 0 or 3x+1 = 0
One of the solutions is that x = 0. Lets find the other.

3x+1=0
3x= -1
x = -1/3

So x1 = 0 and x2 = -1/3. So basically you solve these equations using basic factorization. :)
6 0
3 years ago
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