Answer:
1.75 p
Step-by-step explanation:
if you wouldn't mind giving me brainliest, i'm just trying to rank up.
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Henry has to wrap five presents for a birthday party and has a length of ribbon to make bows for the presents. He cuts the ribbon into eight equal lengths and uses five of the pieces. With the remaining length of ribbon he is able to make six bracelets to give away at the party
I would go with B i had this question on my test and i got it correct
