Given:
The variance of a distribution = 195.
To find:
The standard deviation, rounded to the nearest thousandth.
Solution:
Standard deviation of a distribution is the square root of the variance of the distribution.
Here, the standard deviation of the distribution is
Therefore, the standard deviation is 13.964.
Answer:
a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]
Step-by-step explanation:
a.We know that
e^jθ = cosθ + jsinθ and
e^(-jθ) = cosθ - jsinθ
Adding both equations, we have
e^jθ = cosθ + jsinθ
+
e^(-jθ) = cosθ - jsinθ
e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ
Simplifying, we have
e^jθ + e^(-jθ) = 2cosθ
dividing through by 2 we have
cosθ = ¹/₂[e^jθ + e^(-jθ)]
b. We know that
e^jθ = cosθ + jsinθ and
e^(-jθ) = cosθ - jsinθ
Subtracting both equations, we have
e^jθ = cosθ + jsinθ
-
e^(-jθ) = cosθ - jsinθ
e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)
Simplifying, we have
e^jθ - e^(-jθ) = 2jsinθ
dividing through by 2 we have
sinθ = ¹/₂[e^jθ - e^(-jθ)]
Answer:
3 integers, with values: 1,2,3
Step-by-step explanation:
-2x+1>=-6
2x-1<=6
2x<=7
Positive integers: x=1,2,3
Count: 3
5/6 is not the definite ratio, when you take a larger sample size it could be off by a bit like 499/600 or 501/600
N^2(n - 1) + 3(n - 1)
(n^2 + 3)(n - 1)
the answer is c
