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ivanzaharov [21]
3 years ago
11

Gabriella spent half of her weekly allowance buying pizza. To earn more money her parents let her clean the windows in the house

for $6. What is her weekly allowance if she ended with $14?
Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0
Answer:

22

Explanation:

The problem said that Gabriella spent half her weekly allowance buying pizza.
So we know that whatever her weekly allowance is it has to be cut in half.
If she ended up with $14 then we can double that number and take away 6.

I’m not 100% sure that this is the right answer but I hope it helped!
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Can someone help me with this?
Roman55 [17]

Answer:

Step-by-step explanation:

We first need to figure out how much money Jackie has since Pilar has the same amount of money, but in different coins. Jackie has 24 dimes and 13 quarters, so the amount of money is $2.40 + $3.25 = $5.65; therefore, Pilar has $5.65 also. In order to determine how many nickels and quarters Pilar has, we have to have a system of equations. It's up to us to write the equations we need to solve this. The first equation has to do with the NUMBER of coins Pilar has, the second has to do with the VALUE of each coin. We know that Pilar has only nickels and quarters and that she has a total of 53 coins. So the NUMBER equation is

n + q = 53

The VALUE equation relates how much each coin is worth to the total amount of money it equals:

.05n + .25q = 5.65.

Go back to the first equation and solve it for either n or q. I solved it for n:

n = 53 - q

Plug this into the second equation in place of n now to get:

.05(53 - q) + .25q = 5.65 and

2.65- .05q + .25q = 5.65 and

.20q = 3 so

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n = 38 nickels.

7 0
2 years ago
1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit
Stels [109]
\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})

"Chocolate" has the marginal distribution given by the second column, with a total probability of P(\text{chocolate})=0.35. Similarly, "Adults" has the marginal distribution described by the third row, so that P(\text{adults})=0.60. Then

P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with P(\text{chocolate}\cap\text{adults})=0.21.

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;


P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14
P(\text{children}\cap\text{chocolate})=0.14

c. Yes;

P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26
P(\text{vanilla}\cap\text{children})=0.26
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Step-by-step explanation:

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