How much time is required for a 20 Coulombs charge to flow through a point if the current is 2 amperes? help plzzzzz

Copy the diagram. add a voltmeter to show how you would measure the voltage of the cell

Kruka [31]

Answer: the answer is 23voltage

Explanation: because the voltage and time put together is 23

7 0

3 years ago

An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit

lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is $1.127\times 10^7m/s$

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

$m_1v_1=m_2v_2$

where,

$m_1\text{ and }v_1$ = Initial mass and velocity

$m_2\text{ and }v_2$ = Final mass and velocity

We are given:

$m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s$

Putting values in above equation, we get:

$238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s$

Hence, the velocity of released alpha particle is $1.127\times 10^7m/s$

4 0

3 years ago

If a box is pushed across a floor with a force of 130N. The frictional force acting between the box and the floor is 30N, over a

Sidana [21]

The force acting in the front direction is the 130N.
The frictional force is acting backwards 30N.

1) The net force is 130N - 30N = 100N

2) s = ut + (1/2)at^2    u = 0, Start from rest, s = 25m t =5.

25 = 0*5 + (1/2)* a * 5^2.

25 = 0 + 25/2 * a.

25 = (25/2)a. Divide 25 from both sides.

1 = (1/2)* a. Cross multiply.

2 = a.

a = 2 m/s^2.

3) Mass of the box
Net Force, F = ma
   100 = m*2. Divide both sides by 2.

   100/2 = m
   50    = m.
      m = 50 kg.

4) Final velocity ,   v = u + at.
   v = 0 + 2*5 = 10 m/s.

   Kinetic Energy, K = (1/2) * mv^2.
      = 1/2 * 50 * 10 * 10.
      = 2500 J.

3 0

3 years ago

In a laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 6.7 rev/

Alexxandr [17]

Answer: 7.095 rev

Explanation: since the motion of the washer is of a constant angular acceleration, then Newton's laws of motion applies.

Recall that

ω = ω0 + αt

Where α = angular acceleration = ?

ω = final angular velocity = 6.7rev/s

ω0 = initial angular velocity = 0 rev/s

t = time taken =8.8s

Since the motion of the dryer starts from rest, ω0 = 0, we have that

ω = αt

6.7 = α(8.8)

α = 6.7/8.8

α = 0.76 rev/s²

This value α = 0.76 rev/s² is a constant value and it is the same all through the motion.

When the lid of the washer was lifted, the motion was of a constant deceleration.

Recall that

θ = ω0t + αt²/2

Where θ = angular displacement

Since the washer is now decelerating, the final velocity (ω= 6.7 rev/s) of the accelerating motion now because the initial velocity of the decelerating motion.

Hence ω0 = 6.7 rev/s, α = - 0.76 rev/s² ( negative sign to denote deceleration) and t = 16.5s

By slotting in the parameters into the formulae, we have that

θ = 6.7 (16.5) + (-0.76)(16.5)²/2

θ = 110.55 - 103.455

θ = 7.095 rev

3 0

4 years ago

Gauss's law states that the net electric flux ΦE through any closed Gaussian surface is equal to the net charge inside the surfa

Elodia [21]

The answer is
B. False

8 0

3 years ago