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love history [14]
3 years ago
13

An airplane travels 330 m down the runway before taking off. Assuming that it has constant acceleration, if it starts from rest

and becomes airborne in 9.00 s, how fast (in m/s) is it moving
Physics
1 answer:
liberstina [14]3 years ago
6 0

Under constant acceleration, we have average velocity \bar v over a time interval of duration \Delta t satisfying

\bar v=\dfrac{v+v_0}2=\dfrac{x-x_0}{\Delta t}

where x_0,v_0 are the plane's initial position and velocity (respectively) and x,v are the plane's position and velocity (respectively) after 9.00 seconds. So

\dfrac{v+0\,\frac{\mathrm m}{\mathrm s}}2=\dfrac{330\,\mathrm m-0\,\mathrm m}{9.00\,\mathrm s}\implies v=73.3\,\dfrac{\mathrm m}{\mathrm s}

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