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swat32
3 years ago
11

Suppose nuclear physicists discovered a fission process that always produced two smaller nuclei and only one neutron. Would this

eliminate the danger of meltdown in a nuclear power plant? Why or Why not- ? Explain.
(Thanks to anyone who helps :)
Physics
1 answer:
Mila [183]3 years ago
6 0
Running that process in a power plant would not only eliminate the
danger of a core meltdown, it would also pretty much eliminate the
possibility of getting any nuclear power out of the plant.

The understanding behind your question is correct . . . Neutrons coming
out of one fission go on to get absorbed in other nuclei, and cause the
other ones to fiss.  BUT . . . NOT every free neutron whizzing around in
the core material gets absorbed.  Some of them enter another nucleus
and immediately get spit out.  And some of them never get near another
nucleus at all.  Of all the neutrons produced in one fission, only some
percentage go on to stimulate another one.  So if each fission produced
only one neutron, then the whole process would completely run out of gas
in some amount if time, as the number of free neutrons dwindled and shrank.

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A cart is driven by a large propeller or fan, which can accelerate or decelerate the cart. The cart starts out at the position x
mash [69]

Answer:

The acceleration of the cart is 1.0 m\s^2 in the negative direction.

Explanation:

Using the equation of motion:

Vf^2 = Vi^2 + 2*a*x

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Where Xf is the final position of the cart and Xi the initial position of the cart.

x = 12.5 - 0

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5 0
3 years ago
A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is
kotykmax [81]

323.5 N is the tension in the cable.

Given

Mass of crate(M) = 175.5 kg

Mass of boom(m) = 94.7 kg

The tension, T in the cable can be calculated by taking moments of force about the central point of marked X.

The Angle of the boom with the horizontal can be calculated by

tanθ = 5/10

θ = tan⁻¹(5/10) = 26.56°

Angle of the boom with horizontal is 26.56°

The angle of cable with horizontal can be calculated by

tan B = 4/10

B = tan⁻¹(4/10) = 21.80°

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Taking moments of force about the point X

(Mcosθ + mcosθ) 0.5 = T(sin(θ +B)1

(175.5 × cos 26.56 + 94.7 × cos 26.56 )× 0.5 = T (sin(26.56 + 21.80) X 1

By calculating, we get

Tension(T) = 241.68/0.747

Tension(T) = 323.5 N

Hence, 323.5 N is the tension in the cable.

Learn more about Tension here brainly.com/question/24994188

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