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tiny-mole [99]
3 years ago
10

A baseball bat changes the momentum of a ball with an impulse of 13.8 Nᐧs. What is the average force that the bat exerts on the

ball if it is in contact with the ball for 0.001 secs.
Physics
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

13800 N

Explanation:

Impulse is the product of average force and time expressed as I=Ft where I is the impulse which results into change in momentum, F is the average force and t is the time of impact. Making F the subject of formula then

F=\frac {I}{t}

Substituting I with 13.8 N.s and time, t witg 0.001 s then the average force is calculated as

F=\frac {13.8 N.s}{0.001}=13800N

Therefore, the average force is equivalent to 13800 N

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Answer:

(a) F = 320

(b) = F = -5.1625

Explanation:

The formula that converts degree Celsius (C) to degree Fahrenheit (F) is:

F = 1.8C + 32

Solving (a): F = 2C

Substitute 2C for F in the above equation

F = 1.8C + 32

2C = 1.8C + 32

Collect like terms

2C - 1.8C = 32

0.2C = 32

Multiply both sides by 5

5 * 0.2C = 32 * 5

C = 160

Recall that F = 2C

F = 2 * 160

F = 320

Solving (b): F = ¼C

Substitute ¼C for F in the above formula

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¼C = 1.8C + 32

Convert fraction to decimal

0.25C = 1.8C + 32

Collect like terms

0.25C - 1.8C = 32

-1.55C = 32

Divide both sides by -1.55

C = 32/(-1.55)

C = -32/1.55

C = -20.65

Recall that: F = ¼C

F = -¼ * 20.65

F = -5.1625

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