Can someone do this for me pleeeaassee its due today and idek where to start

Pls help it’s easy ik but I want to make sure of them both I don’t have much time

LuckyWell [14K]

Answer:

To the right

Weight

Explanation:

8 0

2 years ago

How much charge is enclosed by a Gaussian surface through which the electric flux is 6.78 x 10^9 Nm^2\C.

VMariaS [17]

Answer:

q=0.06 C

Explanation:

Given that

Net flux $\phi = 6.78\times 10^{9}\ Nm^2/C$

Lets take charge inside Gaussian surface = q C

We know that

$\phi=\dfrac{q}{\varepsilon _o}$

$\varepsilon _o=8.854\times 10^{-12} farads\ per\ meter$

Now by putting the values in the above equation we get

$6.78\times 10^{9}=\dfrac{q}{8.854\times 10^{-12}}$

$q=6.78\times 10^{9}\times 8.854\times 10^{-12}\ C$

q=0.06 C

Therefore the net charge inside the surface will be 0.06 C.

q=0.06 C

6 0

3 years ago

1. A child sitting 1.2 m from the center of a merry-go-round moves with a speed of 1.1 m/s.

Ne4ueva [31]

Answers:

A) $1m/s^{2}$

B) 22. 5 N

Explanation:

A) Since this situation is related to uniform circular motion, the centripetal acceleration $a_{C}$ of the child is calculated by:

$a_{C}=\frac{V^{2}}{r}$

Where:

$V=1.1 m/s$ is the speed

$r=1.2 m$ is the child's distane to the center (the radius)

Hence:

$a_{C}=\frac{(1.1 m/s)^{2}}{1.2 m}$

$a_{C}=1.008 m/s^{2} \approx 1 m/s^{2}$

B) Knowing th centripetal acceleration and the mass $m=22. 5 kg$ of the child, we can calculate the net horizontal force $F$ by:

$F=m a_{C}$

$F=(22. 5 kg)(1 m/s^{2})$

$F=22. 5 N$

4 0

3 years ago

As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length

grin007 [14]

Answer:

As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g.

Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward).

Question:

If the bottom of your window is a height hb above the ground, what is the velocity vground of the pot as it hits the ground? You may introduce the new variable vb, the speed at the bottom of the window, defined by

vb=Lwt+gt2.

Express your answer in terms of some or all of the variables hb, Lw, t, vb, and g.

The correct answer is

vground = (t²+lw²+(2t³+2t²)×g×Lw+(t⁴+2t³+t²) ) ∧ 0.5 = vb² +2g×vbt+1/2gt²

Explanation:

We have from the relation

v = u + gt, S = ut + 1/2 gt², v² = u² + 2gS

in this case S = hb, u = vb=Lwt+gt2. and v = vground

therefore v² = (Lwt+gt²)² + 2 × g × hb

= (Lwt+gt²)² + 2 × g × (Lwt+gt²)×t + 1/2 gt² = vb² +2g×vbt+1/2gt²

vground = (t²+lw²+(2t³+2t²)×g×Lw+(t⁴+2t³+t²) ) ∧ 0.5

7 0

3 years ago

Compared to yellow light, orange light has

Mkey [24]

<span>So we want to know what does orange light has when we compare it to yellow light. So when we take a look at the electromagnetic spectrum we can see that orange color has longer wavelength than yellow color. So the correct answer is A. alonger wavelength.</span>

7 0

3 years ago

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