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Pavlova-9 [17]
3 years ago
8

Can someone do this for me pleeeaassee its due today and idek where to start

Physics
1 answer:
professor190 [17]3 years ago
5 0
Ummmm i don’t kno I’m sorry
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Which of the following statements about large scale mineral extraction is true?
Sonbull [250]

Answer: D Minarel extraction cannot be done in ways that does not completely destroy the environment

Explanation: Hope this helps !!

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4 years ago
Identify the energy transformations in the following actions.
Artemon [7]
According to the Law of Conservation of Energy, energy is neither created nor destroyed. It is only transferred through different forms of energy. For the following situations, the conversion of energy is as follows:

*Turning on a space heater = electrical energy⇒heat energy
*Dropping an apple core into the garbage =  potential energy⇒kinetic energy
*Climbing up a rope ladder = kinetic energy⇒potential energy
*Starting a car = chemical energy⇒mechanical energy
<span>*Turning on a flashlight = chemical energy</span>⇒electrical energy
4 0
3 years ago
Read 2 more answers
Two metallic rods A and B of different materials have same length. The linear expansivity of A is 12×10–6 oC–1and cubical expans
uysha [10]

Answer:

The length of rod A will be <u>greater than </u>the length of rod B

Explanation:

We, know that the formula for final length in linear thermal expansion of a rod is:

L' = L(1 + ∝ΔT)

where,

L' = Final Length

L = Initial Length

∝ = Co-efficient of linear expansion

ΔT = Change in temperature

Since, the rods here have same original length and the temperature difference is same as well. Therefore, the final length will only depend upon the coefficient of linear expansion.

For Rod A:

∝₁ = 12 x 10⁻⁶ °C⁻¹

For Rod B:

∝₂ = β₂/3

where,

β₂ = Coefficient of volumetric expansion for rod B = 24 x 10⁻⁶ °C⁻¹

Therefore,

∝₂ = 24 x 10⁻⁶ °C⁻¹/3

∝₂ = 8 x 10⁻⁶ °C⁻¹

Since,

∝₁ > ∝₂

Therefore,

L₁ > L₂

So, the length of rod A will be <u>greater than </u>the length of rod B

6 0
3 years ago
A 167-? resistor and a 114-? resistor are both connected in parallel across a power supply. If the potential drop across the 167
Troyanec [42]
19-? Is the exact p.d across the 114-?resistor.
Current will different
But p.d will same in parallel circuit .
7 0
3 years ago
(b) If TH = 500°C, TC = 20°C, and Wcycle = 200 kJ, what are QH and QC, each in kJ?
BigorU [14]

Answer:

QC = 122 KJ

QH = 2.64 x 122 = 322 KJ

Explanation:

TH = 500 Degree C = 500 + 273 = 773 K

TC = 20 degree C = 20 + 273 = 293 K

W cycle = 200 KJ

Use the formula for the work done in a cycle

Wcycle = QH - QC

200 = QH - QC    ..... (1)

Usse

TH / TC = QH / QC

773 / 293 = QH / QC

QH / QC = 2.64

QH = 2.64 QC     Put it in equation (1)

200 = 2.64 QC - QC

QC = 122 KJ

So, QH = 2.64 x 122 = 322 KJ

4 0
3 years ago
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