Answer:
Explanation:
Intensity of unpolarized light = I(o)
Intensity of light after first polarization by polarizer A. = I(o)/2
Angle between A and B = 120 degree.
Intensity of light after second polarization = I Cos² θ
= I(o) /2 x cos²120 = I(o) /8 .
Angle between B and C is 70 degree
Intensity of light after third polarization =
I(o)/8 x Cos² 70 = 0.1156 x I (o) /8 =
Required ratio =.01445
If everyone on earth shouted at the same time, it would make a very loud sound, but perhaps not as loud as you'd think.
soy de texas, united states
I will name block a as Ma=5 kg, block b as Mb=10 kg and mass of the pulley M=3 kg and radius as R. Since the system will accelerate in the direction of the block b because it has greater mass, I will take that direction as positive. Both blocks and the pulley have the same acceleration because the slipping on the pulley is neglected. First, the equations of motion:
Mb*g-Tg=MbαR and
Ta-Ma*g=MaαR,
where Ta and Tb are the tensions of the cord, g=9.81 m/s^2 and α is the angular accereration. Also a=αR where a is the acceleration of the system.
Now the equation of rotational dynamics of a solid body:
(Tb-Ta)R=Iα=(1/2)*M*R^2*α, where (1/2)*M*R^2 is the moment of inertia of a disc.
When we input Tb=Mb*g - Mb*α*R and Ta=Ma*g + Ma*α*R from the first two equations into the third we get: (Mb*g - Mb*α*R - Ma*α*R - Ma*g)*R=(1/2)*M*R^2*α.
We solve for α and get: α=(Mb*g-Ma*g)/((1/2)*MR+Mb*R+Ma*R)=2.97 rad/s^2.
We know that a=α*R and we easily get a=0.4455 m/s^2