Question

How many vibrations per second are associated with a 101-mhz radio wave?

Answer 1

Answer:

$1.01\cdot 10^8$ vibrations per second

Explanation:

The frequency of a wave corresponds to the number of vibrations per second:

$f=\frac{N}{1 s}$ (1)

where N is the number of vibrations per second.

In this problem, the frequency of the radio wave is

$f=101 MHz =1.01\cdot 10^8 Hz$

And substituting into eq.(1), we find N:

$N=f \cdot (1 s)=1.01\cdot 10^8$