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3 years ago

Help y<-1/3x+1 y≤2x-3

Mathematics

1 answer:

patriot [66]3 years ago

3 0

Answer:

-(1/3)x+1>y

2x-3≥y

If x<12/7 then 2x-3≥y

and if x≥12/7 then -(1/3)x+1>y

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23x +5y−2, when x=6 and y=3.

zhenek [66]

Answer:

151

Step-by-step explanation:

Plug in 23(6)+5(3)-2

Simplify 138+15-2

Solve 153-2

151

8 0

3 years ago

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

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3 years ago

How much paper will it take to make each tree including the bottom??

Nataly [62]

The bottom is a square with a side length of 2 ft.

The area of a square is Area = S^2 = 2^2 = 4 square ft. Bottom)

The area of one side ( triangle) = 1/2 x base x height = 1/2 x 2 x 4 = 4 square ft.

There are 4 triangles: 4 x 4 sq. ft. = 16 sq.ft. ( four sides)

Total area = four sides + bottom = 16 + 4 = 20 feet^2

7 0

3 years ago

The function g(x) is a transformation of the quadratic parent function, fx):

77julia77 [94]

Answer: D

Step-by-step explanation:

The graph is narrower, so the coefficient of $x^2$ has an absolute value more than 1.

Eliminate B and C.

Also, because g(x) opens down, the coefficient of $x^2$ is negative.

Eliminate A.

This leaves D as the answer.

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2 years ago

Ann is grouping 38 rocks. She can put them into groups of 10 rocks or as single rocks. what are the different ways Ann can group

PtichkaEL [24]

Color,size,type,smell, glows

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3 years ago

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Help y<-1/3x+1 y≤2x-3​

Help y<-1/3x+1 y≤2x-3