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3 years ago

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2) Compare and contrast the structure of the nucleotide that makes up DNA and the nucleotide that makes up RNA.

1 answer:

SCORPION-xisa [38]3 years ago

3 0

Answer: DNA contains the nucleotides guanine (G), cytosine (C), adenine (A), and thymine (T). RNA contains the nucleotides guanine (G), cytosine (C), uracil (U), and thymine (T). The difference between the two is that RNA contains uracil (U) rather than adenine (A).

The base pairs in DNA are adenine with thymine and guanine with cytosine. The base pairs in RNA are uracil with thymine and guanine with cytosine.

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2 years ago

let A and a represent dominant and recessive alleles whos respective frequencies are p and q in a given interbreeding population

lesantik [10]

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A) $48$ %

B) $18$ %

Explanation:

A) Given

Frequency of individuals in the population having recessive phenotypes $= 16$ %

Frequency of individuals in the population having recessive phenotypes is represented by $q^2$

$q^ 2 = 0.16\\q= \sqrt{0.16}\\ q = 0.4$

Thus frequency of recessive genes is equal to $40%$

frequency of dominant genes is equal to

$p = 1-q\\= 1-0.4\\= 0.6$

Now,

$p^2 + q^2+2pq = 1\\2pq = 1-0.16-0.36\\2pq = 0.48$

$48$ % of genes exist in the heterozygous condition

B.

Frequency of individuals in the population having recessive phenotypes $= 1$ %

Frequency of individuals in the population having recessive phenotypes is represented by $q^2$

$q^ 2 = 0.01\\q= \sqrt{0.01}\\ q = 0.1$

Thus frequency of recessive genes is equal to $10%$

frequency of dominant genes is equal to

$p = 1-q\\= 1-0.1\\= 0.9$

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$p^2 + q^2+2pq = 1\\2pq = 1-0.01-0.81\\2pq = 0.18$

$18$ % of genes exist in the heterozygous condition

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3 years ago