Answer:
In a fruit fly experiment, grey body, normal winged (homozygous dominant) fruit flies were mated with black body, short winged (homozygous recessive) fruit flies. The F1 dihybrid females were then used in a test cross. If the genes are always linked and no crossing over occurs, what would be the predicted ratio in the F2 generation?
GG x bb = Gb, Gb, Gb and Gb F1 generation
grey body heterozygous offspring 4:0
Gb x Gb= GG, Gb, Gb, and bb F2 generation
3:1 three grey body fly and one black body fly
Explanation:
Answer:
maybe abiotic and biotic..?
I'm not 100% sure what you're looking for, sorry!
Explanation:
B. inferior
because it is definitely not any of the others
Answer:
The cell is eukaryotic because it contains mitochondria.
nucleus
Explanation:
Answer:
Some forms of chromatin modification can be passed on to future generation of cells
Acetylation of histone tails in chromatin allows access to DNA for transcription
DNA is not transcribed when packaged tightly in a condensed form
methylation of histone tails can promote condensation of the chromatin
Explanation:
chromatin modifications that can be passed on includes epigenetic modifications that are heritable changes made to the chromatin structure that does not involve the DNA sequences. Some epigenetic modifications include DNA methylation and Histone modifications. examples of histone modification include acetylation, methylation, phosphorylation, ubiquintylation etc. All these function either in allowing the DNA become more accessible to transcritional factors or vice versa. for exmple, histone tail acetylation encourages unwounding of nucleosomes allowing transcriptional factors to have access to the DNa while histone tails methylation further tightens the nucleosomes promoting condensation of the chromatin.
