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3 years ago

I need help on this please

Mathematics

1 answer:

Komok [63]3 years ago

3 0

Answer:

(-4/7 , 23/7) hope this helps

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What is the initial value of e=3h+200.

Dmitrij [34]

Answer:h=e-200/3

Step-by-step explanation:

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3 years ago

Share the things you notice

iogann1982 [59]

Answer:

its a negative correlation and a traingle the a nd c are farther apart then the m and n

Step-by-step explanation:

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3 years ago

Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

Answer: The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

Step-by-step explanation:

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

6 0

3 years ago

Weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. Find the probabi

AlekseyPX

Answer:

$80

Step-by-step explanation:

400÷50= 80 which is the weekly rate of wages

7 0

3 years ago

Read 2 more answers

Francisco and Ryan are stuck simplifying radical expressions. Francisco has simplified to the quantity of x to the one half powe

Wewaii [24]

X to the one half power, over x to the three eighteenth power is equal to x to the one half power, divided by x to the one sixth power, which equals x to the power of (one half minus one sixth), or x to the one third power.

The twenty seventh root of the quantity of x to the second times x to the third times x to the fourth equals the twenty seventh root of x to the ninth power which equals x to the one third power. 

I cannot say whether Francisco and Ryan started with equivalent expressions but on final simplification they ended up the same. One might reasonably assume they started with equivalent expressions, but who knows if they made any mistakes in their simplifications.

4 0

3 years ago

I need help on this please​

I need help on this please