Sven has 11 more than twice as many customers as when he started selling

Type the correct answer in each box. use numerals instead of words. students in a reading class have three options for their boo

Alexus [3.1K]

The answers to the questions on how she would use the colored chips are given here:

brochure 4 blue chips

writing a new article 6 yellow chips

designing a computer presentation 10 red chips

<h3>How to solve for the values</h3>

For the first percentage

20 / 100 = x/20

= 20 * 20 = 100x

400 = 100x

divide through by 100

x = 400/100

x = 4

For the second percentage

30/100 = x/20

600 = 100x

x = 600/100

x = 6

For the last

50/100 = x/20

1000 = 100x

x = 10

The proof is that 6 + 4 + 10 still gives us 20

Read more on percentages here: brainly.com/question/24877689

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4 0

2 years ago

Morgan borrowed $0.35 from her mother every time she went to the gas station to buy some chips. Over the summer Morgan went to t

GarryVolchara [31]

Answer:

The money borrowed by Morgan is $ 3.15.

Step-by-step explanation:

Money borrowed by Morgan to buy chips = $ 0.35

Number of times goes to the station = 9

Money borrowed by Morgan in 9 time visit to station

= 9 x $ 0.35

=$ 3.15

5 0

3 years ago

In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.

Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

$\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}$

where c is the proportionality constant

$\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}$

Hence, x value is 12 when y value is 9

3 0

3 years ago

(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)

laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if $K(t)\neq 0$