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inn [45]
3 years ago
9

Benito and Tamika start at the same point. Benito walks 1.5 miles north in a straight path. Tamika walks 2 miles east in a strai

ght path. How many miles apart are they at the end of their walks rounded to the nearest hundredth mile?​
Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

uuuhhhhhhhhhhhhhhhhhhhhjjjjjjjjjjjjjjjjjjjjjhfdfghhtsdvhtedfniyef

Step-by-step explanation:

ghhhhhtfhfrfbjytddfbnjhhrgvhji

...............buvyctxdx ru vybubyvtctbunubyct ccu buvyftcybubuvtcrctbuhy vfc rx ty vybubyvyvybububtfrfybububub6bubyb

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Equivalent expression of 10+(x divided 16)
Ivahew [28]

Answer:

x/16 + 10

Step-by-step explanation:

10+(x÷16)

To add or subtract expressions, expand them to make their denominators the same. Multiply 10 times 16/16.

10 x 16 / 16 + x/16

Since 10 x 16 / 16 and x/16 have the same denominator, add them by adding their numerators.

10 x 16 + x / 16

Do the multiplications in 10×16+x.

160 + x / 16 = x/16 + 10

4 0
3 years ago
Multiply.<br> 35<br> 22<br> x____
SIZIF [17.4K]

Answer:

35 times 22 equals 770..........

4 0
3 years ago
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Is 20 quart greater than 80 cups
White raven [17]
I think it's equal
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3 0
3 years ago
Name the transformations of the next equation y=3(x+6) - 5
klemol [59]

Answer:

vertical stretch

Step-by-step explanation:

8 0
2 years ago
In the circle below, DB = 22 cm, and m&lt;DBC = 60°. Find BC. Ignore my handwriting.​
Karo-lina-s [1.5K]

Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

6 0
3 years ago
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