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3 years ago

Hi Jose, when you submit this form, the owner will be able to see your name and email address.

Chemistry

1 answer:

Andrei [34K]3 years ago

8 0

Answer:

10460J

Explanation:

Given parameters:

Mass of water sample = 100g

Initial temperature = 35°C

Final temperature = 60°C

Unknown:

Amount of energy absorbed by water = ?

Solution:

The amount of energy absorbed by water is mathematically expressed below;

H = m C ΔT

H is the amount of energy

m is the mass

C is the specific heat capacity of water = 4.184J/g°C

ΔT = 60°C - 35°C = 25°C

Now insert the parameters and solve;

H = 100 x 4.184 x 25 = 10460J

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Answer:

0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM

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C. 2 C(s) + 2 H₂(g) → C₂H₄(g); ΔG°f=68.20 kJ/mol

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Feasible. ΔG°rxn = ΔG°f(product) < 0.

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