3 mol H₂ → 2 mol NH₃
5 mol H₂ → x mol NH₃
x=2*5.0/3=3.3
n(NH₃)=3.3 mol
Answer:
If an insufficient amount of nitrogen were produced, the air bag would under inflate and not provide adequate protection. Clearly, the stoichiometry of the reaction is very important.
C + 2S → CS2 + 89.3 kJ
Moles of CS2 = 150.0 kJ x (1 mol CS2/89.3 kJ) = 1.680 mol CS2
MW of CS2 = (12.01 + 2x32.06) g/mol = 76.13 g/mol
Mass of CS2 = 1.680 mol CS2 × (76.13 g CS2/1 mol CS2) = 128 g CS2
